关闭 RTTI 的简单类的 Boost 序列化 (-fno-rtti)

Question

我正在尝试使用 boost 序列化来序列化具有普通旧数据类型的简单类。然而，我唯一的要求是我不能使用 RTTI。因此，我使用 gcc 4.4.1 for ARM Linux 和最新的 Boost 1.47 库通过 -fno-rtti 进行编译。

这是我的课程：

#include <boost/archive/xml_oarchive.hpp>
#include <boost/archive/xml_iarchive.hpp>

class libNemoMemento
{
    friend class boost::serialization::access;
    private:
        template<class Archive>
        void serialize(Archive & ar, const unsigned int version)
        {
            ar & BOOST_SERIALIZATION_NVP(temperature);
            ar & BOOST_SERIALIZATION_NVP(voltage);
            ar & BOOST_SERIALIZATION_NVP(bandwidth);
            ar & BOOST_SERIALIZATION_NVP(power);
        }
        int temperature;
        unsigned int voltage;
        unsigned int bandwidth;
        unsigned char power;
    public:
        libNemoMemento(void) {}
        virtual ~libNemoMemento(void) {}
};

我什至还没有实现实际的保存和加载功能（从查看 Boost 文档来看，它们似乎非常简单），但我已经收到以下编译器错误：

In file included from /home/me/prebuild/third-party/boost/include/boost/serialization/detail/shared_ptr_132.hpp:29,
                 from /home/me/third-party/boost/include/boost/serialization/shared_ptr_132.hpp:35,
                 from /home/me/third-party/boost/include/boost/archive/shared_ptr_helper.hpp:29,
                 from /home/me/third-party/boost/include/boost/archive/xml_iarchive.hpp:133,
                 from serialize_test.h:21,
                 from serialize_test.cpp:15:
/home/me/third-party/boost/include/boost/serialization/detail/shared_count_132.hpp: In member function 'virtual void* boost_132::detail::sp_counted_base_impl<P, D>::get_deleter(const std::type_info&)':
/home/me/third-party/boost/include/boost/serialization/detail/shared_count_132.hpp:274: error: cannot use typeid with -fno-rtti
In file included from /home/me/prebuild/third-party/boost/include/boost/serialization/shared_ptr_132.hpp:35,
                 from /home/me/prebuild/third-party/boost/include/boost/archive/shared_ptr_helper.hpp:29,
                 from /home/me/prebuild/third-party/boost/include/boost/archive/xml_iarchive.hpp:133,
                 from serialize_test.h:21,
                 from serialize_test.cpp:15:
/home/me/prebuild/third-party/boost/include/boost/serialization/detail/shared_ptr_132.hpp: In function 'D* boost_132::get_deleter(const boost_132::shared_ptr<U>&)':
/home/me/prebuild/third-party/boost/include/boost/serialization/detail/shared_ptr_132.hpp:465: error: cannot use typeid with -fno-rtti
make: *** [all] Error 1

所以..问题是，是否可以使用 boost 序列化来序列化这个简单的类而不使用 RTTI？我环顾四周，似乎可以使用一些 boost 宏和机制（#include < boost/serialization/extended_type_info_no_rtti.hpp > 暗示了这一点），但我是一个新的 Boost 用户，对如何使用非常无能为力继续。

PS：如果删除 -fno-rtti，我的代码可以正常编译。

Answer 1

看看这个：

http://boost.2283326 .n4.nabble.com/boost-serialization-and-RTTI-td2566883.html