SQLite在目标c中插入数据

Question

我想向 mydatabase.sqlite 插入一些数据，但遇到问题。插入数据时没有错误消息，但打开数据库后却看不到任何数据。没有任何数据。

这是MyClass中的addCoffee方法：

if(addStmt == nil) {
    const char *sql = "insert into records(Date, Latitude, Longitude) Values(?, ?, ?)";
    if(sqlite3_prepare_v2(database, sql, -1, &addStmt, NULL) != SQLITE_OK)
        NSAssert1(0, @"Error while creating add statement. '%s'", sqlite3_errmsg(database));
}

sqlite3_bind_text(addStmt, 1, [Date UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_double(addStmt, 2, [Latitude doubleValue] );
sqlite3_bind_double(addStmt, 3, [Longitude doubleValue] );

if(SQLITE_DONE != sqlite3_step(addStmt))
    NSAssert1(0, @"Error while inserting data. '%s'", sqlite3_errmsg(database));
else
    //SQLite provides a method to get the last primary key inserted by using sqlite3_last_insert_rowid
    recordID = sqlite3_last_insert_rowid(database);

//Reset the add statement.
sqlite3_reset(addStmt);

发送数据：

iDailyAppDelegate *appDelegate = (iDailyAppDelegate *)[[UIApplication sharedApplication] delegate];

//Create a MyClass Object.
MyClass *coffeeObj = [[MyClass alloc] initWithPrimaryKey:0];
coffeeObj.Date = dateInString;
NSDecimalNumber *temp = [[NSDecimalNumber alloc] initWithString:first];
coffeeObj.Latitude = temp;
NSDecimalNumber *temp2 = [[NSDecimalNumber alloc] initWithString:second];
coffeeObj.Longitude = temp2;
[temp release];
coffeeObj.isDirty = NO;
coffeeObj.isDetailViewHydrated = YES;

//Add the object
[appDelegate addCoffee:coffeeObj];

Answer 1

- (void)inserting{

    database=nil;
    if (sqlite3_open([[DBAction getSqlitePath] UTF8String], &database) == SQLITE_OK){
        const char *sql = [[NSString stringWithFormat:@"insert  into SiteTable set Site_Address = '%@'",someString] UTF8String];
        sqlite3_stmt *updateStmt = nil;
        if(sqlite3_prepare_v2(database, sql, -1, &updateStmt, NULL) != SQLITE_OK)
        {
            //NSAssert1(0, @"Error while creating update statement. '%s'", sqlite3_errmsg(database));
        }
        if (SQLITE_DONE != sqlite3_step(updateStmt)){
            //NSAssert1(0, @"Error while creating database. '%s'", sqlite3_errmsg(database));
        }
        sqlite3_reset(updateStmt);
        sqlite3_finalize(updateStmt);
    }
    else{
        //NSAssert1(0, @"Error while opening database '%s'", sqlite3_errmsg(database));
    }
    sqlite3_close(database);

}

Answer 2

为发送到数据库的所有 sql 命令创建 NSLog，然后尝试从终​​端执行它们，您将看到所有错误并能够修复它们