CXF RESTful 客户端 - 如何在没有 Spring 的情况下进行基本的 http 身份验证？

发布于 2024-12-11 16:22:32 字数 851 浏览 0 评论 0原文

我熟悉使用 Jersey 创建 RESTful Web 服务服务器和客户端，但由于类加载问题，我正在尝试将 Jersey 客户端转换为 CXF。我相信我想使用以 HTTP 为中心的客户端，但我们不使用 Spring。我们需要使用基本的 HTTP 身份验证。用户指南有以下示例：

WebClient client = WebClient.create("http:books", "username", "password", "classpath:/config/https.xml");

第一个参数是' t 一个 URI 字符串。这是Spring使用的格式吗？这个方法只能用于使用Spring创建WebClient吗？

显示的另一种进行身份验证的方法是添加标头字符串：

String authorizationHeader = "Basic " + org.apache.cxf.common.util.Base64Utility.encode("user:password".getBytes());
webClient.header("Authorization", authorizationHeader);

我猜测 "user:password" 应该替换为真实值，但希望得到确认。

原文

I am familiar with using Jersey to create RESTful webservice servers and clients, but due to class loading issues, I am trying to convert a Jersey client into CXF. I believe I want to use an HTTP-centric client but we don't use Spring. We need to use basic HTTP authentication. The user guide has this example:

WebClient client = WebClient.create("http:books", "username", "password", "classpath:/config/https.xml");

The first parameter isn't a URI string. Is it a format used by Spring? Can this method only be used to create WebClients using Spring?

The other way of doing authentication shown is to add a header string:

String authorizationHeader = "Basic " + org.apache.cxf.common.util.Base64Utility.encode("user:password".getBytes());
webClient.header("Authorization", authorizationHeader);

I am guessing that "user:password" should be substituted with the real values, but would appreciate confirmation.

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帥小哥 2024-12-18 16:22:32

这个答案来自 CXF 用户邮件列表。

上面引用的第一个示例中有一个拼写错误。它已更新为：

WebClient client = WebClient.create("http://books", "username", "password", "classpath:/config/https.xml");

如果未使用 Spring 配置文件（因此 Spring），第四个参数可以为 null。

所以，这对我有用：

private WebClient webClient;

public RESTfulClient(String url, String username, String password)
        throws IllegalArgumentException
{
    this.username = username;
    this.password = password;
    this.serviceURL = url;

    if (username == null || password == null || serviceURL == null)
    {
        String msg = "username, password and serviceURL MUST be defined.";
        log.error(msg);
        throw new IllegalArgumentException(msg);
    }

    webClient = WebClient.create(this.serviceURL,
            this.username,
            this.password,
            null); // Spring config file - we don't use this
}

This answer came from the CXF users mailing list.

The first example referenced above had a typo in it. It has been updated to:

WebClient client = WebClient.create("http://books", "username", "password", "classpath:/config/https.xml");

The fourth argument can be null if a Spring config file is (and therefore Spring) is not being used.

So, this worked for me:

private WebClient webClient;

public RESTfulClient(String url, String username, String password)
        throws IllegalArgumentException
{
    this.username = username;
    this.password = password;
    this.serviceURL = url;

    if (username == null || password == null || serviceURL == null)
    {
        String msg = "username, password and serviceURL MUST be defined.";
        log.error(msg);
        throw new IllegalArgumentException(msg);
    }

    webClient = WebClient.create(this.serviceURL,
            this.username,
            this.password,
            null); // Spring config file - we don't use this
}

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