SBT：遍历项目依赖图

发布于 2024-12-11 12:51:59 字数 815 浏览 0 评论 0原文

我有一个多模块 Web 项目，其依赖关系图与此类似

WAR-project
- A1
-- A2
-- A3
- B1
-- B2
---- B22
-- B3

，即 war 项目依赖于 A1，而后者又依赖于 A2 和 A3等等。

现在，在打包 war 项目之前，我想将一些 Web 资源从其依赖项目复制到 web 应用程序中。所以我的问题是如何以编程方式遍历 SBT 项目的依赖关系图？即在伪代码中

resourcesToCopy = []
visitedProjects = []
traverseProjectDependencies(project) {
  visitedProjects += project
  if(project has resourceFolder) {
    resourcesToCopy += resourceFolder.getPath
  }
  for(projectDependency in project) {
    if(projectDependency is not visited) {
      traverseProjectDependencies(projectDependency)
    }
  }
}

注意我知道，如果我将资源文件夹添加到每个依赖项的类路径中，那么我可以从 Web 项目中的 fullClasspath 检索它。但我想避免这种解决方案，而且在其他情况下，以编程方式遍历和连接依赖项可能会很有用。

原文

I have a multimodule web project with a dependency graph similar to this

WAR-project
- A1
-- A2
-- A3
- B1
-- B2
---- B22
-- B3

that is the war project depends on A1 which in turn depends on A2 and A3 and so on.

Now prior to the packageing of the war project I want to copy some web resources from its dependent projects into the webapp. So my question is how do I programmatically traverse a SBT project's dependency graph ? i.e. in pseudu code

resourcesToCopy = []
visitedProjects = []
traverseProjectDependencies(project) {
  visitedProjects += project
  if(project has resourceFolder) {
    resourcesToCopy += resourceFolder.getPath
  }
  for(projectDependency in project) {
    if(projectDependency is not visited) {
      traverseProjectDependencies(projectDependency)
    }
  }
}

Note I am aware that if I add the resource folder to the classpath of each of the dependencies then I could retrieve it from the fullClasspath in the web project. But I would like to avoid this solution and also there are other scenarios where programmatically traversing and interfacing with dependencies could be useful.

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凉薄对峙 2024-12-18 12:51:59

以下代码添加了一个aggr-res任务，该任务将聚合依赖项目的所有资源：

val aggrRes= TaskKey[Seq[File]]("aggr-res", "show aggregate resources")

val aggrResTask = aggrRes in Compile <<= {
  (thisProjectRef, buildStructure) flatMap aggrResources(resources in Compile)
}

def aggrResources[T](key: ScopedTask[Seq[T]])(proj: ProjectRef, struct: Load.BuildStructure) = {
  val deps = collectDeps(_.dependencies.map(_.project))(proj, struct)
  deps.flatMap(key in (_, Compile) get struct.data).join.map(_.flatten)
}

def collectDeps(op: ResolvedProject => Seq[ProjectRef])(projRef: ProjectRef, struct: Load.BuildStructure): Seq[ProjectRef] = {
  val deps = Project.getProject(projRef, struct).toSeq.flatMap(op)
  deps.flatMap(ref => ref +: collectDeps(op)(ref, struct)).distinct
}

我已经用一个更完整的示例来说明要点此处

The following code adds a aggr-res task that will aggregate all resources for dependent projects:

val aggrRes= TaskKey[Seq[File]]("aggr-res", "show aggregate resources")

val aggrResTask = aggrRes in Compile <<= {
  (thisProjectRef, buildStructure) flatMap aggrResources(resources in Compile)
}

def aggrResources[T](key: ScopedTask[Seq[T]])(proj: ProjectRef, struct: Load.BuildStructure) = {
  val deps = collectDeps(_.dependencies.map(_.project))(proj, struct)
  deps.flatMap(key in (_, Compile) get struct.data).join.map(_.flatten)
}

def collectDeps(op: ResolvedProject => Seq[ProjectRef])(projRef: ProjectRef, struct: Load.BuildStructure): Seq[ProjectRef] = {
  val deps = Project.getProject(projRef, struct).toSeq.flatMap(op)
  deps.flatMap(ref => ref +: collectDeps(op)(ref, struct)).distinct
}

I have made a gist with a more complete example here

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