如何使用lua模式匹配获取字符串

发布于 2024-12-11 12:40:32 字数 1518 浏览 0 评论 0原文

下面是我的字符串

local Amount =[[
Customer Details Net Amount
# Seq Name
Amount NTR
1 CDABCDEFGHIJ00564
0,1234
2 CDABCDEFGHIJ00565
0,0361
3 CDABCDEFGHIJ00566
0,0361
4 CDABCDEFGHIJ00567
0,0722
5 CDABCDEFGHIJ00568
0,0000
6 CDABCDEFGHIJ00569
0,0000
7 CDABCDEFGHIJ00570
0,0000
8 CDABCDEFGHIJ00571
0,7091
9 CDABCDEFGHIJ00572
1,4240
10 CDABCDEFGHIJ00573
0,0361
11 CDABCDEFGHIJ00574
0,5790
12 CDABCDEFGHIJ00575
0,4060
13 CDABCDEFGHIJ00576
0,3610
14 CDABCDEFGHIJ00577
0,6859
15 CDABCDEFGHIJ00578
0,2888
16 CDABCDEFGHIJ00579
0,0000
17 CDABCDEFGHIJ00580
0,0000
18 CDABCDEFGHIJ00581
0,0000
19 CDABCDEFGHIJ00582
0,0000
20 CDABCDEFGHIJ00583
0,0000
21 CDABCDEFGHIJ00584
0,0000
22 CDABCDEFGHIJ00585
0,8978
23 CDABCDEFGHIJ00586
0,0000
24 CDABCDEFGHIJ00587
2,3882
25 CDABCDEFGHIJ00588
0,0000
26 CDABCDEFGHIJ00589
2,0216
27 CDABCDEFGHIJ00590
1,7540
28 CDABCDEFGHIJ00591
0,0000
29 CDABCDEFGHIJ00592
0,0722
30 CDABCDEFGHIJ00593
0,0361
31 CDABCDEFGHIJ00594
0,0000
32 CDABCDEFGHIJ00595
0,0000
Total NAT files
11,9269
Direct inquiries to:
]]

,基本上是从上面的字符串执行下面的代码

local ptrn = '\n([%d%p]+)\n'
for val1, val2 in string.gmatch(Amount, ptrn) do

    print ("val1:=\t" .. (val1 or '').."\tval2:=\t"..(val2 or ''))

end

,我想获取字符串的最后 5 位数字,即 val1 中的 00564 和 val2 变量中的金额 0,1234,但所有这些都应该采用一种模式。这是一条记录,每条记录都以数字开头,例如这是第 1 条记录或行

1 CDABCDEFGHIJ00564
    0,1234

,这是第 2 条记录或行,依此类推,

 2 CDABCDEFGHIJ00565
    0,0361

请帮忙......

below is my string

local Amount =[[
Customer Details Net Amount
# Seq Name
Amount NTR
1 CDABCDEFGHIJ00564
0,1234
2 CDABCDEFGHIJ00565
0,0361
3 CDABCDEFGHIJ00566
0,0361
4 CDABCDEFGHIJ00567
0,0722
5 CDABCDEFGHIJ00568
0,0000
6 CDABCDEFGHIJ00569
0,0000
7 CDABCDEFGHIJ00570
0,0000
8 CDABCDEFGHIJ00571
0,7091
9 CDABCDEFGHIJ00572
1,4240
10 CDABCDEFGHIJ00573
0,0361
11 CDABCDEFGHIJ00574
0,5790
12 CDABCDEFGHIJ00575
0,4060
13 CDABCDEFGHIJ00576
0,3610
14 CDABCDEFGHIJ00577
0,6859
15 CDABCDEFGHIJ00578
0,2888
16 CDABCDEFGHIJ00579
0,0000
17 CDABCDEFGHIJ00580
0,0000
18 CDABCDEFGHIJ00581
0,0000
19 CDABCDEFGHIJ00582
0,0000
20 CDABCDEFGHIJ00583
0,0000
21 CDABCDEFGHIJ00584
0,0000
22 CDABCDEFGHIJ00585
0,8978
23 CDABCDEFGHIJ00586
0,0000
24 CDABCDEFGHIJ00587
2,3882
25 CDABCDEFGHIJ00588
0,0000
26 CDABCDEFGHIJ00589
2,0216
27 CDABCDEFGHIJ00590
1,7540
28 CDABCDEFGHIJ00591
0,0000
29 CDABCDEFGHIJ00592
0,0722
30 CDABCDEFGHIJ00593
0,0361
31 CDABCDEFGHIJ00594
0,0000
32 CDABCDEFGHIJ00595
0,0000
Total NAT files
11,9269
Direct inquiries to:
]]

by executing the code below

local ptrn = '\n([%d%p]+)\n'
for val1, val2 in string.gmatch(Amount, ptrn) do

    print ("val1:=\t" .. (val1 or '').."\tval2:=\t"..(val2 or ''))

end

basically from the above string I want to fetch the last 5 digits of the string which is 00564 in val1 and the amount which is 0,1234 in val2 variable, but all this should in one pattern. This is a record, every record is starting with a number like this is 1 record or row

1 CDABCDEFGHIJ00564
    0,1234

and this is 2nd record or row and so on

 2 CDABCDEFGHIJ00565
    0,0361

plese help....

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妄司 2024-12-18 12:40:32

在我看来, %d+%s+%a+(%d+)\n%s*([%d,]+) 应该可以解决问题:第一个 %d+ 将捕获行号,%s+ 以匹配后面的空格。 %a+(%d+) 将匹配 CDABCDEFGHIJ00592 并捕获最后的数字(但无法指定您需要恰好五个数字)。 \n%s* 将匹配换行符和下一行上的任何空格,([%d,]+) 将捕获带逗号的最后一个数字。

It seems to me that %d+%s+%a+(%d+)\n%s*([%d,]+) should do the trick: the first %d+ will catch the row number, %s+ to match the white space after. %a+(%d+) will match CDABCDEFGHIJ00592 and capture the digits in the end (no way to specify that you want exactly five digits though). \n%s* will match the newline and any white space on the next line and ([%d,]+) will capture the last number with the comma.

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