一次仅显示可扩展列表的一个子项

发布于 2024-12-11 12:28:31 字数 75 浏览 6 评论 0原文

是否可以一次仅展开 ExpandableListView 的一个子项,从而打开第二个子项将关闭之前打开的子项?

Is it possible to only expand one child of an ExpandableListView at a time, thus opening a second child would close the previously opened child?

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评论(4

耶耶耶 2024-12-18 12:28:31

只是为了确认 bos 在代码中的答案:

    expandableList.setOnGroupExpandListener(new OnGroupExpandListener() {
        int previousGroup = -1;

        @Override
        public void onGroupExpand(int groupPosition) {
            if(groupPosition != previousGroup)
                expandableList.collapseGroup(previousGroup);
            previousGroup = groupPosition;
        }
    });

Just to confirm bos's answer in code:

    expandableList.setOnGroupExpandListener(new OnGroupExpandListener() {
        int previousGroup = -1;

        @Override
        public void onGroupExpand(int groupPosition) {
            if(groupPosition != previousGroup)
                expandableList.collapseGroup(previousGroup);
            previousGroup = groupPosition;
        }
    });
对岸观火 2024-12-18 12:28:31

我不知道有任何自动方法可以实现此目的,但您可以实现 ExpandableListView.OnGroupClickListener,在其中为除被单击的列表组之外的所有列表组运行 collapseGroup() 。这将做你想做的事。

I'm not aware of any automatic methods for this, but you can implement ExpandableListView.OnGroupClickListener, in where you run collapseGroup() for all list groups except the one being clicked. This will do what you want.

命硬 2024-12-18 12:28:31

FastAdapter 中的 withOnlyOneExpandedItem()

您还可以简单地使用位于 FastAdapter 外部库中的 作者:mikepenz

例如,我在抽屉中使用它

drawer.getAdapter().withOnlyOneExpandedItem(true);

Also you can simple use the withOnlyOneExpandedItem() which is in FastAdapter

that is in FastAdapter External Library by mikepenz

For example as I am using it in my Drawer

drawer.getAdapter().withOnlyOneExpandedItem(true);
谁对谁错谁最难过 2024-12-18 12:28:31

您可以将其用于各种条件,就像您在扩展列表中所做的那样 -

      expList.setOnChildClickListener(new OnChildClickListener() 
        {
         @Override
         public boolean onChildClick(ExpandableListView parent, View v,
           int childGroupPosition, int childPosition, long id) {

        // Log.e("OnChildClickListener", "OK "+childGroupPosition+"  "+childPosition);javainterviewquestion
             if(childGroupPosition ==0 && childPosition == 0)
             {

             }
             if(childGroupPosition ==0 && childPosition == 1)
             {

             } 

          return false; 
         }
        });

you can use this for various conditions as you want to do in expansion of list -

      expList.setOnChildClickListener(new OnChildClickListener() 
        {
         @Override
         public boolean onChildClick(ExpandableListView parent, View v,
           int childGroupPosition, int childPosition, long id) {

        // Log.e("OnChildClickListener", "OK "+childGroupPosition+"  "+childPosition);javainterviewquestion
             if(childGroupPosition ==0 && childPosition == 0)
             {

             }
             if(childGroupPosition ==0 && childPosition == 1)
             {

             } 

          return false; 
         }
        });
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