等待另一项工作结束后再开始一项工作

发布于 2024-12-11 08:31:56 字数 375 浏览 2 评论 0原文

我在哈德逊有两份工作，A 和 A。 B.

如果 A 的构建已经在进行中，我只想将 B 放入队列中。实际上我想将A设置为B的上游项目，但不将A设置为下游项目（加上“上游项目正在构建时阻止构建”高级选项），因为我不需要每次触发A时都构建B。

由于 B 构建步骤是一个 python 脚本，我知道我可以

http://myhudson/srs/job/A/api/json?tree=builds[building]

定期轮询并等待顶部 building 结果中的 true 值，但在此轮询期间，B 将“在进度”，并且只有 B 处于队列中会更清楚。

有什么建议吗？谢谢！

原文

I have two jobs on Hudson, A & B.

I just want to put B in queue if a build of A is already on-going.
Actually I would like to set A as upstream project of B but without setting A as downstream project (plus "Block build when upstream project is building" advanced option), because I don't need to build B each time A is triggered.

As B build step is a python script, I know I can poll

http://myhudson/srs/job/A/api/json?tree=builds[building]

periodically and wait for a true value in top building result, but during this polling, B will be "in progress", and it would be clearer to just have B in queue.

Any suggestions?
Thanks!

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