使用 sed 从日志文件中提取目录
我正在尝试解析 application.log，其中有许多行遵循以下相同的语法。
"Error","jrpp-237","10/13/11","02:55:04",,"File not found: /indexUsa~.cfm The specific sequence of files included or processed is: c:\websites\pj7fe4\indexUsa~.cfm '' "
我需要使用某种类型的命令来提取 c:\websites\ 和下一个 \ 之间列出的内容，
例如在本例中它将是 pj7fe4< /code>
我认为以下命令会起作用。
bin/sed -n '/c:\\websites\\/,/\\/p' upload/test.log
不幸的是，通过进一步阅读，我现在了解到这将通过 \ 返回包含 c:\websites 的整行，并且我需要知道中间的部分，而不是整条线。
更困难的是，我需要匹配所有目录子路径，而不仅仅是某一特定行，因为这是针对多个站点的。
I'm trying to parse through an application.log that has many lines that follow the same syntax below.
"Error","jrpp-237","10/13/11","02:55:04",,"File not found: /indexUsa~.cfm The specific sequence of files included or processed is: c:\websites\pj7fe4\indexUsa~.cfm '' "
I need to use some type of command to pull out what is listed between c:\websites\ and the next \
e.g. in this case it would be pj7fe4
I thought that the following command would work..
bin/sed -n '/c:\\websites\\/,/\\/p' upload/test.log
Unfortunately from reading further I now understand that this will return the entire line containing c:\websites through the \ and I need to know the in between, not the whole line.
To be more difficult I need to match all of the directory sub paths, not just one particular line as this is for multiple sites.
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您错误地使用了范围模式。您不能使用它来将命令（在本例中为打印）限制为行的一部分，而只能限制为行的范围。你也无法逃脱退格键。
试试这个：
sed 's/.*c:\\websites\\\([0-9a-zA-Z]*\)\\.*/\1/'有一个很好的 sed教程在这里：Sed - Bruce Barnett 的介绍和教程
You're using range patterns incorrectly. You can't use it to limit the command (print in this case) to a part of the line, only to a range of lines. You also don't escape the backspaces.
Try this:
sed 's/.*c:\\websites\\\([0-9a-zA-Z]*\)\\.*/\1/'There's a good sed tutorial here: Sed - An Introduction and Tutorial by Bruce Barnett
grep 方式：
测试：
grep way:
test: