Makefile：在先决条件中使用目标文件路径
我有以下项目结构：
+-Makefile
+-src/
+-a/
| +-foo.py
+-b/
| +-foo.py
+-c/
| +-foo.py
每个 foo.py 文件都是一个具有完全相同名称的不同文件（即它们具有不同的索引节点，但字面上都称为“foo.py” - 当然实际上是这样）名称不是 foo.py，这只是一个示例）。
我希望创建一个 GNU Makefile 规则，该规则在运行时会创建以下结构：
+-Makefile
+-src/
+-a/
| +-foo.py
| +-a.zip
+-b/
| +-foo.py
| +-b.zip
+-c/
| +-foo.py
| +-c.zip
这是我能够弄清楚的最接近的结构，尽管它当然会由于在似乎不允许的先决条件：
SRCDIR = src/
PRJ_DIRS = a b c
SRC_FILE = foo.py
# This next rather nasty line turns PRJ_DIRS in to, e.g., src/a/a.zip etc.
ZIP_FILES = $(addprefix $(SRCDIR),$(join $(PRJ_DIRS),$(PRJ_DIRS:%=/%.zip)))'
build: $(ZIP_FILES)
# Next line crashes because we can't use $@ in the prereq
$(ZIP_FILES): $(addprefix $(dir $@), $(SRC_FILE))
touch $@
所以提出问题的一种方法是： 如何编写一条规则，使用每个相应的 foo.py 文件作为构建适当的 .zip 文件的先决条件？
或者，一个可能实际上正在寻找的更直接的问题从错误的角度来看： 如何引用先决条件中构建的特定目标？
I have the following project structure:
+-Makefile
+-src/
+-a/
| +-foo.py
+-b/
| +-foo.py
+-c/
| +-foo.py
Each foo.py file is a different file with exactly the same name (ie they have different inodes but are all literally called 'foo.py' - although of course in reality the name is not foo.py, which is just an example).
I wish to create a GNU Makefile rule which, when run, creates the following structure:
+-Makefile
+-src/
+-a/
| +-foo.py
| +-a.zip
+-b/
| +-foo.py
| +-b.zip
+-c/
| +-foo.py
| +-c.zip
This is the closest I have been able to figure out, although of course it fails due to using a target variable in the prereqs which doesn't seem to be allowed:
SRCDIR = src/
PRJ_DIRS = a b c
SRC_FILE = foo.py
# This next rather nasty line turns PRJ_DIRS in to, e.g., src/a/a.zip etc.
ZIP_FILES = $(addprefix $(SRCDIR),$(join $(PRJ_DIRS),$(PRJ_DIRS:%=/%.zip)))'
build: $(ZIP_FILES)
# Next line crashes because we can't use $@ in the prereq
$(ZIP_FILES): $(addprefix $(dir $@), $(SRC_FILE))
touch $@
So one way to put the question:
How can I write a rule the uses each corresponding foo.py file as a prereq to build the appropriate .zip file?
Or, a more direct question that might actually be looking at this from the wrong angle:
How can I refer to the specific target that's being built in the prereqs?
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好吧，既然你认为二次扩展是一种拼凑，那么
$(foreach ...)和$(eval ...)再次可以拯救你（一个非常强大的组合） 。将您的规则替换为以下内容，您应该得到您想要的。
define rule $(SRCDIR)$(1)/$(1).zip: $(SRCDIR)$(1)/$(SRC_FILE) touch $@ endef $(foreach dir, $(PRJ_DIRS), $(eval $(call rule,$(dir))))Okay, since you consider secondary expansion a kludge, it's
$(foreach ...)and$(eval ...)to the rescue again (a very powerful combination).Replace your rule with the following and you should get what you want.
define rule $(SRCDIR)$(1)/$(1).zip: $(SRCDIR)$(1)/$(SRC_FILE) touch $@ endef $(foreach dir, $(PRJ_DIRS), $(eval $(call rule,$(dir))))