如何围绕另一个向量2旋转一个向量2？
我目前正在制作一款游戏。该游戏由玩家从自上而下的角度操作机器人组成。移动、碰撞和射击全部实现。
然而，机器人有 2 个“手臂”，可以从这些手臂发射武器，为了从这些手臂射击，我基本上设置了 2 个临时位置供机器人发射，每个手臂一个，包括 X 方向的偏移+/- 15. 当玩家向下看时，手臂射击得很好，子弹似乎是从机器人手臂中射出的，但是，当我转动玩家在 Y 轴上向左或向右看时，它显示为虽然机器人正在发射子弹它的体内。我有一张图片可以帮助说明问题
http://imageshack.us/photo /my-images/694/problemrs.png/
正如您所看到的，在机器人身体旋转之前，左右射弹生成点都处于正确的位置。我想要做的是沿着机器人身体旋转这 2 个 Vector2 位置。红色块显示射弹的产卵位置，白色块代表我希望的产卵位置。我尝试了一些旋转方法，但没有一个在之后产生效果。
有什么线索吗？
I'm currently in the process of making a game. he game consists of the player operating a robot from a top down perspective. The movement, collisions and firing is all implemented.
However, the robot has 2 'arms' from which it fires its weapons, to fire from these arms i have basically set up 2 makeshift locations for the robot to fire from, one for each arm, consisting of an offset in the X direction of +/- 15. When the player is looking down the arms shoot fine and the bullets appear to be coming out from the robots arms, however, when i turn the player to look to the left or right on the Y axis, it appears as though the robot is shooting the bullets from within its body. I have an image to help illustrate the issue
http://imageshack.us/photo/my-images/694/problemrs.png/
As you can see, the left and right projectile spawn points are in the correct position until the robots body is rotated. What i want to be able to do, is rotate those 2 Vector2 positions around alongside the robots body. The red blocks show where the projectiles are spawning from, and the white blocks represent where i would like the spawn position to be. I've tried a few rotation methods but none have had the effect im after.
Any clues?
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您可以使用仿射变换来做到这一点......但是，就您而言，使用基本三角函数可能更容易做到这一点。
令
X、Y为机器人的位置。令
T为机器人的旋转角度。令
DX为从机器人中心到“手臂”的距离。 （对另一只手臂使用 -DX）。ArmX= (cos(T) *DX) +XArmY= ( sin(T) *DX) +YYou could do it with an affine transform... but, in your case, it might be easier to do it with basic trig.
LET
X,Ybe the location of the robot.LET
Tbe the angle of rotation of the robot.LET
DXbe the distance from the center of the robot to the "arm". (use -DX for the other arm).ArmX= (cos(T) *DX) +XArmY= (sin(T) *DX) +Y我想，你的机器人有一个前进方向和一个中心，然后
I suppose, you have a forward direction and a center for your robot, then
看来您正确地旋转了向量本身。您缺少的部分是您需要将矢量的基部/尾部的位置（它开始的位置）编码为矢量并旋转它。
It looks like you're rotating the vectors themselves correctly. The part you're missing is that you need to encode the position of the base/tail of your vector (the place it starts from) as a vector and rotate that as well.