如何在不阻塞执行的情况下编写 System.Diagnostic.Process 输出？

发布于 2024-12-10 22:33:22 字数 1175 浏览 0 评论 0原文

我正在尝试编写一个在 Mono Gtk / .NET 中播放卡拉 OK 的简单软件。我只是想通过 shell 运行类似“timidity filename.kar”的东西（timidity 是一个软件合成器）。我想将胆怯输出写入文本视图，但问题是，如果我运行此代码，胆怯开始“播放”，但应用程序退出

protected virtual void OnBtnPlayClicked (object sender, System.EventArgs e) { 字符串参数 = filechooser.Filename; 字符串输出=“”；字符串错误 = string.Empty;

    ProcessStartInfo psi = new ProcessStartInfo("timidity", parms);

    psi.RedirectStandardOutput = true;
    psi.RedirectStandardError = true;
    psi.WindowStyle = System.Diagnostics.ProcessWindowStyle.Normal;
    psi.UseShellExecute = false;

    System.Diagnostics.Process reg;
    reg = System.Diagnostics.Process.Start(psi);

    reg.OutputDataReceived += new DataReceivedEventHandler(SortOutputHandler);
reg.BeginOutputReadLine();     // HERE THE APP GO CRASH

}

  private void SortOutputHandler(object sendingProcess, 
        DataReceivedEventArgs outLine)
    {
        // Collect the sort command output.
        if (!String.IsNullOrEmpty(outLine.Data))
        {                
            txtOutput.Buffer.Text =txtOutput.Buffer.Text + outLine.Data;

        }
    }

我哪里错了？

谢谢

原文

i'm trying to write a simple software who play karaoke in Mono Gtk / .NET.
I simply want to run via shell something like "timidity filename.kar" (timidity is a software synth).
I want to write timidity output into a textview, but the problem is that if i run this code, timidity start to 'play' but the app exits

protected virtual void OnBtnPlayClicked (object sender, System.EventArgs e)
{
string parms = filechooser.Filename;
string output = "";
string error = string.Empty;

    ProcessStartInfo psi = new ProcessStartInfo("timidity", parms);

    psi.RedirectStandardOutput = true;
    psi.RedirectStandardError = true;
    psi.WindowStyle = System.Diagnostics.ProcessWindowStyle.Normal;
    psi.UseShellExecute = false;

    System.Diagnostics.Process reg;
    reg = System.Diagnostics.Process.Start(psi);

    reg.OutputDataReceived += new DataReceivedEventHandler(SortOutputHandler);
reg.BeginOutputReadLine();     // HERE THE APP GO CRASH

}

  private void SortOutputHandler(object sendingProcess, 
        DataReceivedEventArgs outLine)
    {
        // Collect the sort command output.
        if (!String.IsNullOrEmpty(outLine.Data))
        {                
            txtOutput.Buffer.Text =txtOutput.Buffer.Text + outLine.Data;

        }
    }

Where i'm wrong ?

Thanks

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不必了 2024-12-17 22:33:22

您正在尝试 ReadToEnd 生成的进程的标准输出，这将阻塞，直到该进程关闭其标准输出流。在这种情况下，这将是进程终止的时间。

相反，您需要做的是重定向标准输出，并使用 BeginOutputReadLine。

例如：

psi.UseShellExecute = false;
psi.RedirectStandardOutput = true;
reg = System.Diagnostics.Process.Start(psi);
reg.OutputDataReceived += (sender, args) => 
                          Console.WriteLine("received output: {0}", args.Data);
reg.BeginOutputReadLine();

You are attempting to ReadToEnd of the spawned process's standard output, which will block until that process closes its standard output stream. In this case, this will be when the process terminates.

What you need to do instead is redirect the standard output and read chunks out of it as they become available using BeginOutputReadLine.

For example:

psi.UseShellExecute = false;
psi.RedirectStandardOutput = true;
reg = System.Diagnostics.Process.Start(psi);
reg.OutputDataReceived += (sender, args) => 
                          Console.WriteLine("received output: {0}", args.Data);
reg.BeginOutputReadLine();

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