Ruby 正则表达式：分割字符串并匹配以换行符或字符串开头开头的匹配项？
这是我为此使用的正则表达式。我使用 Ruby，如果我没记错的话，它使用 POSIX 正则表达式。
regex = /(?:\n^)(\*[\w+ ?]+\*)\n/
这是我的目标：我想用一个正则表达式分割一个字符串，该正则表达式是*由星号分隔*，包括那些星号。 但是：我只想按以换行符 (\n) 开头的匹配项进行分割，或者它是整个字符串的开头。这是我正在使用的字符串。
"*Friday*\nDo not *break here*\n*But break here*\nBut again, not this"
我的正则表达式在 *Friday* 匹配时没有正确拆分，但在 *But Break here* 匹配时正在拆分（它也是在这里进行拆分）。我的问题出在第一组中的某个地方，我认为： (?:\n^) — 我知道这是错误的，而且我不完全确定正确的编写方式。有人可以透露一些信息吗？这是我的完整代码。
regex = /(?:\n^)(\*[\w+ ?]+\*)\n/
str = "*Friday*\nDo not *break here*\n*But break here*\nBut again, not this"
str.split(regex)
结果是这样的：
>>> ["*Friday*\nDo not *break here*", "*But break here*", "But again, not this"]
我希望它是这样的：
>>> ["*Friday*", "Do not *break here*", "*But break here*", "But again, not this"]
编辑#1：我已经更新了我的正则表达式和结果。 (2011/10/18 16:26 CST)
编辑#2：我再次更新了两者。 （中部标准时间 16:32）
Here's my regular expression that I have for this. I'm in Ruby, which — if I'm not mistaken — uses POSIX regular expressions.
regex = /(?:\n^)(\*[\w+ ?]+\*)\n/
Here's my goal: I want to split a string with a regex that is *delimited by asterisks*, including those asterisks. However: I only want to split by the match if it is prefaced with a newline character (\n), or it's the start of the whole string. This is the string I'm working with.
"*Friday*\nDo not *break here*\n*But break here*\nBut again, not this"
My regular expression is not splitting properly at the *Friday* match, but it is splitting at the *But break here* match (it's also throwing in a here split). My issue is somewhere in the first group, I think: (?:\n^) — I know it's wrong, and I'm not entirely sure of the correct way to write it. Can someone shed some light? Here's my complete code.
regex = /(?:\n^)(\*[\w+ ?]+\*)\n/
str = "*Friday*\nDo not *break here*\n*But break here*\nBut again, not this"
str.split(regex)
Which results in this:
>>> ["*Friday*\nDo not *break here*", "*But break here*", "But again, not this"]
I want it to be this:
>>> ["*Friday*", "Do not *break here*", "*But break here*", "But again, not this"]
Edit #1: I've updated my regex and result. (2011/10/18 16:26 CST)
Edit #2: I've updated both again. (16:32 CST)
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如果只是在每个字符串前面添加一个 '\n' 会怎么样？这大大简化了处理过程：
我们必须注意最初的额外匹配，但这还不错。我怀疑有人可以缩短这个时间。
What if you just add a '\n' to the front of each string. That simplifies the processing quite a bit:
We have to watch for the initial extra match but it's not too bad. I suspect someone can shorten this a bit.
第 1 组和第 1 组下面的正则表达式 2 ：
将为您提供所需的输出。我不是红宝石专家，所以你必须自己创建列表:)
Groups 1 & 2 of the regex below :
Will give you your desired output. I am no ruby expert so you will have to create the list yourself :)
为什么不直接在换行符处分割呢？从你的例子来看，这看起来就是你真正想做的事情。
Why not just split at newlines? From your example, it looks that's what you're really trying to do.