数组搜索中的通配符

发布于 2024-12-10 17:20:33 字数 188 浏览 0 评论 0原文

是否可以在 array_search 中使用通配符？我想搜索字符串的一部分，然后搜索

类似的内容（带星号）

print $pos = array_search('abitofastring%', $vars['myarray']);
unset($vars['myarray'][$pos]);

原文

Is is possible to use wildcards with array_search? I want to search for part of a string and then

something like(with an asterisk)

print $pos = array_search('abitofastring%', $vars['myarray']);
unset($vars['myarray'][$pos]);

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毁虫ゝ 2024-12-17 17:20:33

是否可以在 array_search 中使用通配符？

否，但您可以使用正则表达式（支持通配符）和 preg_grep 函数。

示例：

$array = explode(',', "House,Car,Boat,Horse,Pool Boy");

# remove all strings from array that do not contain "ho"

$array = preg_grep('~ho~i', $array, PREG_GREP_INVERT);

则数组为：

Array
(
    [1] => Car
    [2] => Boat
    [4] => Pool Boy
)

由于编写正则表达式模式可能很复杂，因此使用一个辅助函数将 SQL LIKE 模式转换为正则表达式可能会很方便，这样可以更轻松地使用：

$array = explode(',', "House,Car,Boat,Horse,Pool Boy");

# Search for "Ho" at the beginning of each string

$regex = like_to_regex('Ho%');

$array = preg_grep($regex, $array, PREG_GREP_INVERT);

print_r($array);

/**
 * convert a MySQL LIKE pattern into a pcre pattern
 */
function like_to_regex($like, $casesensitive = FALSE, $escapechar = '\\')
{
    $pattern = sprintf('~(?<!%1$s)(%1$s{2}|%%|_)~', preg_quote($escapechar));
    $tokens = preg_split($pattern, $like, 0, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
    foreach($tokens as &$token)
    {
        switch($token)
        {
            case $escapechar.$escapechar:
                $token = preg_quote($escapechar);
                break;
            case '_':
                $token = '.';
                break;
            case '%':
                $token = '.*';
                break;
            default:
                $token = preg_quote($token);

        }
    }
    return sprintf('~^%s$~%s', implode('', $tokens), $casesensitive ? '':'i');
}

Is is possible to use wildcards with array_search?

No, but you can use regular expressions (which supports wildcards) and the preg_grep function.

Example:

$array = explode(',', "House,Car,Boat,Horse,Pool Boy");

# remove all strings from array that do not contain "ho"

$array = preg_grep('~ho~i', $array, PREG_GREP_INVERT);

The array then is:

Array
(
    [1] => Car
    [2] => Boat
    [4] => Pool Boy
)

As it can be complicated to write regular expression patterns, it might be handy to have a helper function that converts your SQL LIKE pattern into a regular expression so this can be more easily used:

$array = explode(',', "House,Car,Boat,Horse,Pool Boy");

# Search for "Ho" at the beginning of each string

$regex = like_to_regex('Ho%');

$array = preg_grep($regex, $array, PREG_GREP_INVERT);

print_r($array);

/**
 * convert a MySQL LIKE pattern into a pcre pattern
 */
function like_to_regex($like, $casesensitive = FALSE, $escapechar = '\\')
{
    $pattern = sprintf('~(?<!%1$s)(%1$s{2}|%%|_)~', preg_quote($escapechar));
    $tokens = preg_split($pattern, $like, 0, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
    foreach($tokens as &$token)
    {
        switch($token)
        {
            case $escapechar.$escapechar:
                $token = preg_quote($escapechar);
                break;
            case '_':
                $token = '.';
                break;
            case '%':
                $token = '.*';
                break;
            default:
                $token = preg_quote($token);

        }
    }
    return sprintf('~^%s$~%s', implode('', $tokens), $casesensitive ? '':'i');
}

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