从 C# 调用 F# 对象的接口方法

发布于 2024-12-10 16:44:11 字数 601 浏览 0 评论 0原文

给定 F# 类型：

type Foo() =
    member this.Prop with get() = ()

    interface IDisposable with
        member this.Dispose() = ()

在 C# 中，我创建对象，但无法调用 Dispose()：

var x = new Foo();
x.Dispose(); // compile error, x does not contain a definition of Dispose

但是，我可以写：

((IDisposable)x).Dispose(); // works, but I don't like the cast

有什么方法可以避免 C# 中的强制转换吗？这是否与 F# 不会自动让您从 F# 中调用 Foo 类型上的 .Dispose() 相关？

原文

Given an F# type:

type Foo() =
    member this.Prop with get() = ()

    interface IDisposable with
        member this.Dispose() = ()

In C#, I create the object, but I can't call Dispose():

var x = new Foo();
x.Dispose(); // compile error, x does not contain a definition of Dispose

However, I can write:

((IDisposable)x).Dispose(); // works, but I don't like the cast

Is there any way to avoid the cast in C#? Is this related to the way F# doesn't automatically let you call .Dispose() on the Foo type from within F#?

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想念有你 2024-12-17 16:44:11

默认情况下，F# 中的接口实现是显式的。因此，除非从转换为接口的类型（某种形式的转换）中看到，否则这些方法是不可见的。

要解决此问题，请公开一个与接口版本具有相同签名的实例方法。然后将接口转发到实例函数。例如

type Foo() =
    member this.Prop with get() = ()
    member this.Dispose() = ()

    interface IDisposable with
        member this.Dispose() = this.Dispose()

Interface implementations in F# are explicit by default. Hence the methods are not visible unless seen from the type converted to the interface (some form of casting).

To work around this expose an instance method which has the same signature as the interface version. Then have the interface on forward to the instance function. For example

type Foo() =
    member this.Prop with get() = ()
    member this.Dispose() = ()

    interface IDisposable with
        member this.Dispose() = this.Dispose()

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