MySQL 查询选择和计算值

发布于 2024-12-10 13:00:58 字数 479 浏览 1 评论 0原文

SELECT 
if('1000'>plan_limit_max,'1000'-plan_limit_max,0) as 'Overage',
if(`per_hour_cost`='0', `per_period_cost`+'10'*`Overage`, per_hour_cost*720) AS 'Total'

FROM `service_price`

order by Total asc
;

第 3 行出现 Overage 错误有

Error Code: 1054. Unknown column 'Overage' in 'field list'

没有办法通过一个查询来完成我想要的操作？我想按总价对结果进行排序，但要计算它，我必须计算超出限制的使用情况。

我知道应该有其他方法可以做到这一点，使用多个查询，创建视图等。我只是想知道是否有更简单的查询。

原文

SELECT 
if('1000'>plan_limit_max,'1000'-plan_limit_max,0) as 'Overage',
if(`per_hour_cost`='0', `per_period_cost`+'10'*`Overage`, per_hour_cost*720) AS 'Total'

FROM `service_price`

order by Total asc
;

There is an error with Overage at line 3

Error Code: 1054. Unknown column 'Overage' in 'field list'

Is there a way to do what I want with one query?
I want to order results by total price, but to calculate it I have to calculate the usage exceeds the limit.

I know there should be other ways to do it, use more than one queries, create views, etc..
I just wonder if there is a simpler query for this.

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寒尘 2024-12-17 13:00:58

您可以在子查询中计算一次Overage：

SELECT Overage,
       IF(per_hour_cost = 0, per_period_cost + 10 * Overage, per_hour_cost * 720)
         AS Total
  FROM (SELECT IF(1000 > plan_limit_max, 1000 - plan_limit_max, 0) AS Overage,
               service_price.*
          FROM service_price) d;

You can compute Overage once, in a subquery:

SELECT Overage,
       IF(per_hour_cost = 0, per_period_cost + 10 * Overage, per_hour_cost * 720)
         AS Total
  FROM (SELECT IF(1000 > plan_limit_max, 1000 - plan_limit_max, 0) AS Overage,
               service_price.*
          FROM service_price) d;

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山有枢 2024-12-17 13:00:58

Overage 未定义为查询的一部分，仅定义为结果中的列标题。您无法引用该列，因为它还不存在...您必须使用类似于下面的 SQL 的内容：

SELECT 
if('1000'>plan_limit_max,'1000'-plan_limit_max,0) as 'Overage',
if(`per_hour_cost`='0', `per_period_cost`+'10'*if('1000'>plan_limit_max,'1000'-             plan_limit_max,0), 
per_hour_cost*720) AS 'Total'

FROM `service_price`

order by Total asc

Overage is not defined as part of the query, only as the column header in the result. You cannot reference that column as it does not yet exist... You've got to use something like the SQL below:

SELECT 
if('1000'>plan_limit_max,'1000'-plan_limit_max,0) as 'Overage',
if(`per_hour_cost`='0', `per_period_cost`+'10'*if('1000'>plan_limit_max,'1000'-             plan_limit_max,0), 
per_hour_cost*720) AS 'Total'

FROM `service_price`

order by Total asc

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冬天旳寂寞 2024-12-17 13:00:58

您在 OVERAGE 中输入“``”时出错。您必须在 OVERAGE 中使用“”。

SELECT 
if('1000'>plan_limit_max,'1000'-plan_limit_max,0) as 'Overage',
if(`per_hour_cost`='0', `per_period_cost`+'10'* 'Overage', per_hour_cost*720) AS 'Total'

FROM `service_price`

order by Total asc
;

You have an error putting " `` " in OVERAGE. You must use ' ' in OVERAGE.

SELECT 
if('1000'>plan_limit_max,'1000'-plan_limit_max,0) as 'Overage',
if(`per_hour_cost`='0', `per_period_cost`+'10'* 'Overage', per_hour_cost*720) AS 'Total'

FROM `service_price`

order by Total asc
;

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~没有更多了~