检查点是否包含在矩形内时出错

Question

好吧，我正在制作一个简单的 Tic Tac Toe 程序。现在，我正在使用 MouseListener 检查鼠标单击的位置，并查看鼠标单击了 9 个空格中的哪 1 个。我想检查以确保矩形检查正常工作，因此每次鼠标单击控制台都会显示 9 个字母的字符串。字母是e=空x=X o=O。但是看起来这个矩形似乎不包含任何坐标。这是一些代码片段：

package com.blackattack.tictactoe;

import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Rectangle;
import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;

import javax.swing.JPanel;

public class TicTacToePanel extends JPanel implements MouseListener {

    Graphics2D g2d;
    Rectangle[] bounds = new Rectangle[9];
    TicTacToeLogic board = new TicTacToeLogic();
    int STATE = 0;
    final int PLAYING = 0;
    final int LOSS = 1;
    final int WIN = 2;
    Win w = new Win(false, "e");



    public TicTacToePanel() {
        super();
        addMouseListener(this);

        bounds[0] = new Rectangle(0, 0, getWidth()/3, getHeight()/3);
        bounds[1] = new Rectangle(getWidth()/3, 0, getWidth()/3, getHeight()/3);
        bounds[2] = new Rectangle((getWidth()/3)*2, 0, getWidth()/3, getHeight()/3);

        bounds[3] = new Rectangle(0, getHeight()/3, getWidth()/3, getHeight()/3);
        bounds[4] = new Rectangle(getWidth()/3, getHeight()/3, getWidth()/3, getHeight()/3);
        bounds[5] = new Rectangle((getWidth()/3)*2, getHeight()/3, getWidth()/3, getHeight()/3);

        bounds[6] = new Rectangle(0, getHeight()/3, (getWidth()/3)*2, getHeight()/3);
        bounds[7] = new Rectangle(getWidth()/3, (getHeight()/3)*2, getWidth()/3, getHeight()/3);
        bounds[8] = new Rectangle((getWidth()/3)*2, (getHeight()/3)*2, getWidth()/3, getHeight()/3);
    }
//paintComponent would be here
@Override
    public void mouseClicked(MouseEvent e) {
        int x = getX();
        int y = getY();
        if(bounds[0].contains(x, y)) {
            board.changeState(0, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        if(bounds[1].contains(x, y)) {
            board.changeState(1, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        if(bounds[2].contains(x, y)) {
            board.changeState(2, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        if(bounds[3].contains(x, y)) {
            board.changeState(3, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        if(bounds[4].contains(x, y)) {
            board.changeState(4, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        if(bounds[5].contains(x, y)) {
            board.changeState(5, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        if(bounds[6].contains(x, y)) {
            board.changeState(6, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        if(bounds[7].contains(x, y)) {
            board.changeState(7, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        if(bounds[8].contains(x, y)) {
            board.changeState(8, "x");
            w = board.isWin();
            board.aiPlayerChoose();
            w = board.isWin();
        }
        System.out.println(board.board[0] + " " + board.board[1] + " " + board.board[2] + " " + board.board[3] + " " + board.board[4] + " " + board.board[5] + " " + board.board[6] + " " + board.board[7] + " " + board.board[8]);

    }

所以在这里我检查鼠标是否单击了 9 个空格中的 1 个，然后输出“游戏板” 这是 TicTacToeLogic 的一部分，以便您可以更好地理解：

public class TicTacToeLogic {

    String[] board = { "e", "e", "e", "e", "e", "e", "e", "e", "e" };

    public TicTacToeLogic() {

    }

    public void changeState(int pos, String val) {
        board[pos] = val;
    }

    public void aiPlayerChoose() {
        boolean ready = true;
        while (ready) {
            Random r = new Random();
            int which = r.nextInt(8);
            if (board[which].equals("e")) {
                board[which] = "o";
                ready = false;
            }
        }
    }
}

我似乎无法查明问题所在。当我打印出 board[n] 时，它总是显示为一堆 e。这和我在构造函数中调用 getWidth 和 getHeight 有关系吗？预先感谢，

安德鲁

Answer 1

您认为这是由在构造函数中调用 getWidth 和 getHeight 引起的理论是一个很好的理论。您可以通过检查调试器来验证这一点，甚至只是添加一些 println 或日志记录语句来查看这些方法返回的值。

如果这就是问题所在（我猜是这样），那么您可以通过将大小计算移动到在调整大小时触发的侦听器/方法来修复它。

Answer 2

当您在构造函数中时，getWidth() 和 getHeight() 将返回 0。当窗口布局时，这些值由 LayoutManager 设置。

您需要从 mouseClicked 内计算您的边界。