了解数组访问(处理)
大家好,有人可以帮助我理解兰顿蚂蚁草图中的这段特定代码吗?
antLoc = new int[]{rows/2,columns/2};
我不太明白这里实际发生了什么,这是上下文的其余代码。 (最初来自这里http://www.openprocessing.org/visuals/?visualID=13653)
boolean[][] state;
int[] antLoc;
int antDirection;
int squareSize = 5;
int columns, rows;
color bgCol = color(0,128,128);
color antCol = color (255,0,0);
color sqCol = color(128,128,128);
void setup(){
size(800,600);
background(bgCol);
columns = width/squareSize;
rows = height/squareSize;
state = new boolean[rows][columns];
for(int j = 0; j < rows; j++){
for(int i = 0; i < columns; i++){
state[j][i] = false;
}
}
antLoc = new int[]{rows/2,columns/2};
antDirection = 1;
}
void drawScene(){
fill(sqCol);
for(int j = 0; j < rows; j++){
for(int i = 0; i < columns; i++){
if(state[j][i]){
rect(i*squareSize,j*squareSize,squareSize,squareSize);
}
}
}
fill(antCol);
rect(antLoc[1]*squareSize,antLoc[0]*squareSize,squareSize,squareSize);
}
void turnLeft(){
if (antDirection > 1){
antDirection--;
} else{
antDirection = 4;
}
}
void turnRight(){
if (antDirection < 4){
antDirection++;
} else {
antDirection = 1;
}
}
void moveForward(){
if (antDirection == 1){
antLoc[0]--;
}
if (antDirection == 2){
antLoc[1]++;
}
if (antDirection == 3){
antLoc[0]++;
}
if (antDirection == 4){
antLoc[1]--;
}
}
void updateScene(){
moveForward();
if (state[antLoc[0]][antLoc[1]] == false){
state[antLoc[0]][antLoc[1]] = true;
turnRight();
} else {
state[antLoc[0]][antLoc[1]] = false;
turnLeft();
}
}
void draw(){
background(bgCol);
drawScene();
for(int i = 0; i < 10; i++){
updateScene();
}
}
Hi could anybody help me understand this particular piece of code from this Langton's Ant sketch.
antLoc = new int[]{rows/2,columns/2};
I don't exactly understand what is actually happening here, here is the rest of the code for context. (originally from here http://www.openprocessing.org/visuals/?visualID=13653)
boolean[][] state;
int[] antLoc;
int antDirection;
int squareSize = 5;
int columns, rows;
color bgCol = color(0,128,128);
color antCol = color (255,0,0);
color sqCol = color(128,128,128);
void setup(){
size(800,600);
background(bgCol);
columns = width/squareSize;
rows = height/squareSize;
state = new boolean[rows][columns];
for(int j = 0; j < rows; j++){
for(int i = 0; i < columns; i++){
state[j][i] = false;
}
}
antLoc = new int[]{rows/2,columns/2};
antDirection = 1;
}
void drawScene(){
fill(sqCol);
for(int j = 0; j < rows; j++){
for(int i = 0; i < columns; i++){
if(state[j][i]){
rect(i*squareSize,j*squareSize,squareSize,squareSize);
}
}
}
fill(antCol);
rect(antLoc[1]*squareSize,antLoc[0]*squareSize,squareSize,squareSize);
}
void turnLeft(){
if (antDirection > 1){
antDirection--;
} else{
antDirection = 4;
}
}
void turnRight(){
if (antDirection < 4){
antDirection++;
} else {
antDirection = 1;
}
}
void moveForward(){
if (antDirection == 1){
antLoc[0]--;
}
if (antDirection == 2){
antLoc[1]++;
}
if (antDirection == 3){
antLoc[0]++;
}
if (antDirection == 4){
antLoc[1]--;
}
}
void updateScene(){
moveForward();
if (state[antLoc[0]][antLoc[1]] == false){
state[antLoc[0]][antLoc[1]] = true;
turnRight();
} else {
state[antLoc[0]][antLoc[1]] = false;
turnLeft();
}
}
void draw(){
background(bgCol);
drawScene();
for(int i = 0; i < 10; i++){
updateScene();
}
}
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您提到的行:
大致类似于:
为了方便起见,它只是语法简写。
The line you mention:
is broadly similar to:
It's just syntactic shorthand, for convenience.
您的代码创建一个长度为 2 的新
int
数组,并使用给定表达式初始化元素。它相当于:Your code creates a new array of
int
with length 2, and initialises the elements with the given expressions. It is equivalent to: