使用正则表达式从 url 获取 id

Question

http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F1234567
http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F1234567%2Fsubtitle
http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F123456
http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F123456%2Fsubtitle
http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F1234567%2F
http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F123456%2F

URL 始终以以下形式开头：

http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F

id 始终为数字，但位数可能会有所不同。

如何从上面的示例 URL 获取 id（1234567 和 123456）？

我尝试使用以下模式但没有成功（它不返回任何匹配项）：

/^http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F(\d)$/

Answer 1

我建议您首先解析此网址并提取网址 查询字符串参数并对其进行 url 解码：

function getParameterByName(url, name)
{
  name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
  var regexS = "[\\?&]" + name + "=([^&#]*)";
  var regex = new RegExp(regexS);
  var results = regex.exec(url);
  if(results == null)
    return "";
  else
    return decodeURIComponent(results[1].replace(/\+/g, " "));
}

如下所示：

var url = 'http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F1234567';
var p = getParameterByName(url, 'url');

然后使用一些正则表达式来解析 p 并提取必要的信息，例如 /\d+/。

Answer 2

使用正确的 URL 解析函数，您可以执行以下操作：

parse_str(parse_url($url, PHP_URL_QUERY), $params);
if (isset($params['url'])) {
    parse_str(parse_url($params['url'], PHP_URL_QUERY), $params);
    if (isset($params['movie'])) {
        $movie = $params['movie'];
    }
}

Answer 3

$urls = array(
   'http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F1234567'
   , 'http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F1234567%2Fsubtitle'
   , 'http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F123456'
   , 'http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F123456%2Fsubtitle'
   , 'http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F1234567%2F'
   , 'http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F123456%2F'
);

foreach ($urls as $url) {
   if (preg_match('/%2Fmovie%2F(\d+)/', $url, $matches)) {
      var_dump($matches[1]);
   }
}

吻。我原本打算使用 parse_url()，但无论如何都无法在没有正则表达式的情况下解析查询字符串。

Answer 4

还有一种不解析的方法。假设 $url = URL

http://codepad.org/t91DK9H2

$url = "http://example.com/movie.swf?url=http%3A%2F%2Fexample.com%2Fmovie%2F1234567%2Fsubtitle";
$reg = "/^([\w\d\.:]+).*movie%2F(\d+).*/";
$id = preg_replace($reg,"$2",$url);

Answer 5

看来您需要转义一些特殊字符。
尝试：

/^http ://example.com/movie.swf\?url=http%3A%2F%2Fexample.com%2Fmovie%2F(\d+)$/