如何从超类方法调用 python 子类方法？
我有以下类型的超类/子类设置：
class SuperClass(object):
def __init__(self):
self.do_something() # requires the do_something method always be called
def do_something(self):
raise NotImplementedError
class SubClass(SuperClass):
def __init__(self):
super(SuperClass, self).__init__() # this should do_something
def do_something(self):
print "hello"
我希望 SuperClass init 始终调用尚未实现的 do_something 方法。我正在使用 python 2.7。或许ABC可以做到这一点，但是还有别的办法吗？
谢谢。
I have the following kind of superclass / subclass setup:
class SuperClass(object):
def __init__(self):
self.do_something() # requires the do_something method always be called
def do_something(self):
raise NotImplementedError
class SubClass(SuperClass):
def __init__(self):
super(SuperClass, self).__init__() # this should do_something
def do_something(self):
print "hello"
I would like the SuperClass init to always call a not-yet-implemented do_something method. I'm using python 2.7. Perhaps ABC can do this, but it is there another way?
Thanks.
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除了使用
super之外，您的代码大部分都是正确的。您需要将当前类名放入super调用中，因此：由于您输入了错误的类名，因此未调用
SuperClass.__init__，并且结果do_something也没有被调用。Your code is mostly correct, except for the use of
super. You need to put the current class name in thesupercall, so it would be:Since you put in the wrong class name,
SuperClass.__init__wasn't called, and as a resultdo_somethingwasn't called either.