使用“类”作为 Mako 宏的一个选项
我正在编写一个 Mako 扩展来帮助渲染表单。我取得了巨大的进步，直到我遇到了关于 css 类的一大障碍。我想编写如下所示的代码：
<%fp:form method="post" action="" class="css-class"%>
...content
</%fp:form>
fp:form 引用的函数看起来就像这样：
@supports_caller
def form(context, **kwargs):
#...
当我运行此代码时，我收到以下异常：
SyntaxException: (SyntaxError) invalid syntax (<unknown>, line 1) (u"fp.form(method=u'post',action=u'',class=u'css-class')") at line: 1 char: 52
仅当指定“class”属性时才会发生这种情况，大概是因为 Mako 是将属性直接转换为关键字参数，而不是字典解包。我尝试向我的函数传递一个特殊的“attrs”参数，但似乎没有好的方法将字典传递给 Mako：
<%fp:form method="post" action="" attrs="${{'class':'css-class'}}"%>
#SyntaxError: invalid syntax
<%fp:form method="post" action="" attrs="${dict(class='css-class')}"%>
#Won't work - can't pass 'class' directly as a keyword argument!
那么我该如何解决这个问题呢？我知道我可以指定一个特殊的属性，例如“css_class”并将其转换为类，但这有点麻烦，并进一步阻止库每次生成带有 css_class 属性的表单。
I am writing a Mako extension that assist in rendering forms. I was making excellent progress until I ran into one big stumbling block regarding css classes. I want to write code that looks like this:
<%fp:form method="post" action="" class="css-class"%>
...content
</%fp:form>
The function that fp:form refers to looks simply like:
@supports_caller
def form(context, **kwargs):
#...
When I run this code, I get the following exception:
SyntaxException: (SyntaxError) invalid syntax (<unknown>, line 1) (u"fp.form(method=u'post',action=u'',class=u'css-class')") at line: 1 char: 52
This only happens when the "class" attribute is specified, presumably because Mako is converting the attributes directly to keyword arguments rather than dictionary unpacking. I tried passing a special "attrs" argument to my function, but there seems to be no good way to pass a dict to Mako:
<%fp:form method="post" action="" attrs="${{'class':'css-class'}}"%>
#SyntaxError: invalid syntax
<%fp:form method="post" action="" attrs="${dict(class='css-class')}"%>
#Won't work - can't pass 'class' directly as a keyword argument!
So how do I get around this? I know I can specify a special attribute, like "css_class" and convert that into class, but that's a bit of a hack and further prevents the library from every producing a form with an attribute with css_class.
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没有办法解决这个问题，因为
class是一个关键字，并且总是这样解析。人们通常使用class_来代替。There is no way around this because
classis a keyword and is always parsed as such. People usually useclass_instead.