PHP 抛出的错误消息与我想要的不同
我有一个 Javascript 函数，它在我的服务器上调用 PHP 脚本。如果发生故障，JS 函数期望从脚本接收 save_failed 消息。
出于测试目的，我在下面的行中放入了错误的数据库信息，因此它失败了：
mysql_connect("hostname", "user", "pass") or die('save_failed');
但是，JS 函数的行为不符合预期，并且似乎没有收到 save_failed 作为输出。为了确认，我将收到的消息显示为警报框，这就是我得到的。
为什么 php 脚本不抛出 save_failed 以及如何让它这样做？
I have a Javascript function which calls a PHP script on my server. In case of failures, the JS function is expecting to receive a message of save_failed from the script.
For testing purposes, I put the wrong database info in the line below so that it fails:
mysql_connect("hostname", "user", "pass") or die('save_failed');
However, the JS function was not behaving as expected, and it seemed it wasn't receiving save_failed as the output. To confirm, I displayed the message being received as an alert box and this is what I got.
Why is the php script not throwing just save_failed and how can I make it do that?
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您已经安装了 Xdebug，并且正在发生更多错误。
在生产中，您应该有
error_reporting(0)和ini_set('display_errors', “0”）。You have Xdebug installed and further errors are occurring.
In production, you should have
error_reporting(0)andini_set('display_errors', '0').