如何在 Go 中使用与包同名的变量名？

发布于 2024-12-10 03:06:58 字数 424 浏览 0 评论 0原文

文件或目录的常见变量名称是“path”。不幸的是，这也是 Go 中包的名称。此外，在 DoIt 中更改路径作为参数名称，如何编译此代码？

package main

import (
    "path"
    "os"
)

func main() {
    DoIt("file.txt")
}

func DoIt(path string) {
    path.Join(os.TempDir(), path)
}

我得到的错误是：

$6g pathvar.go 
pathvar.go:4: imported and not used: path
pathvar.go:13: path.Join undefined (type string has no field or method Join)

原文

A common variable name for files or directories is "path". Unfortunately that is also the name of a package in Go. Besides, changing path as a argument name in DoIt, how do I get this code to compile?

package main

import (
    "path"
    "os"
)

func main() {
    DoIt("file.txt")
}

func DoIt(path string) {
    path.Join(os.TempDir(), path)
}

The error I get is:

$6g pathvar.go 
pathvar.go:4: imported and not used: path
pathvar.go:13: path.Join undefined (type string has no field or method Join)

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冬天旳寂寞 2024-12-17 03:06:58

路径字符串正在隐藏导入的路径。您可以做的是将导入包的别名设置为例如pathpkg，方法是将import中的行“path”更改为pathpkg“path”，这样代码的开头是这样的

package main

import (
    pathpkg "path"
    "os"
)

当然，然后您必须将 DoIt 代码更改为：

pathpkg.Join(os.TempDir(), path)

The path string is shadowing the imported path. What you can do is set imported package's alias to e.g. pathpkg by changing the line "path" in import into pathpkg "path", so the start of your code goes like this

package main

import (
    pathpkg "path"
    "os"
)

Of course then you have to change the DoIt code into:

pathpkg.Join(os.TempDir(), path)

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驱逐舰岛风号 2024-12-17 03:06:58

package main

import (
    "path"
    "os"
)

func main() {
    DoIt("file.txt")
}

// Just don't introduce a same named thing in the scope
// where you need to use the package qualifier.
func DoIt(pth string) {
    path.Join(os.TempDir(), pth)
}

package main

import (
    "path"
    "os"
)

func main() {
    DoIt("file.txt")
}

// Just don't introduce a same named thing in the scope
// where you need to use the package qualifier.
func DoIt(pth string) {
    path.Join(os.TempDir(), pth)
}

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