fs.watch 在 Mac OSX 上通过 Node 0.5.9

发布于 2024-12-10 02:09:02 字数 1046 浏览 3 评论 0原文

我在 Node v0.5.9 上运行以下命令：

var fs = require("fs");
fs.watch("/Users/username/testingFsWatcher/",function(event,file) {
  console.dir(arguments);
});

然后执行以下操作：

cd /Users/username/testingFsWatcher/
>file1 --> { '0': '重命名', '1': null }
mkdir new_folder --> { '0': '重命名', '1': null }
>new_folder/file2 -->没有事件触发/输出
touch file1 -->没有事件触发/输出
rm file1 --> { '0': 'rename', '1': null }

我注意到有两件事似乎不正确：不监视子目录 (new_folder) 以及监视更新/修改文件不会触发 change 事件。查看节点代码并进行测试，似乎这些应该是可能的。

那么，是否可以使用 fs.watch 来监视一个目录及其所有子目录？是否至少可以从文件修改中获取事件？另外，据我所知，fs.watch 由 kqueue 支持，它与 eventid 绑定（在 OSX 中），是否可能获取该 eventid？

注意：我专门使用 fs.watch 而不是 fs.watchFile 因为我需要监视整个目录（最好也是它的所有子目录:)。

感谢您的帮助！

原文

I'm running the following on Node v0.5.9:

var fs = require("fs");
fs.watch("/Users/username/testingFsWatcher/",function(event,file) {
  console.dir(arguments);
});

I then do:

cd /Users/username/testingFsWatcher/
>file1 --> { '0': 'rename', '1': null }
mkdir new_folder --> { '0': 'rename', '1': null }
>new_folder/file2 --> no event triggered/output
touch file1 --> no event triggered/output
rm file1 --> { '0': 'rename', '1': null }

Two things I noticed that seem incorrect: subdirectories (new_folder) are not watched and updates/modifications to watched files do not trigger a change event. Looking over the node code and tests it seems like these should be possible.

So, is it possible to get fs.watch to watch a directory and all of it's subdirectories? Is it at least possible to get an event from a file modification? Also, from what I can tell, fs.watch is backed by kqueue which is tied to an eventid (in OSX), is it possible to get that eventid?

Note: I'm specifically using fs.watch and not fs.watchFile because I need to watch an entire directory (preferably all of it's subdirectories too :).

Thanks for the help!

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