根据从下拉菜单中选择的值,不输出正确的回波
我想使用回显从下拉菜单中输出值,但即使下拉菜单工作正常,回显也不会输出从下拉菜单中选择的正确值。 echo 仅输出会话 ID,仅此而已。你能帮我解决这个问题吗?回声位于代码的底部。
以下是我的代码:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Exam Interface</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>
<p><strong>NOTE: </strong>If a search box is left blank, then the form will search for all data under that specific field</p>
<form action="exam_interface.php" method="post" name="sessionform"> <!-- This will post the form to its own page"-->
<p>Session ID: <input type="text" name="sessionid" /></p> <!-- Enter Session Id here-->
<p>Module Number: <input type="text" name="moduleid" /></p> <!-- Enter Module Id here-->
<p>Teacher Username: <input type="text" name="teacherid" /></p> <!-- Enter Teacher here-->
<p>Student Username: <input type="text" name="studentid" /></p> <!-- Enter User Id here-->
<p>Grade: <input type="text" name="grade" /></p> <!-- Enter Grade here-->
<p>Order Results By: <select name="order">
<option value="ordersessionid">Session ID</option>
<option value="ordermoduleid">Module Number</option>
<option value="orderteacherid">Teacher Username</option>
<option value="orderstudentid">Student Username</option>
<option value="ordergrade">Grade</option>
</select>
<p><input type="submit" value="Submit" name="submit" /></p>
</form>
<?php
$username="u0867587";
$password="31may90";
$database="mobile_app";
mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die("Unable to select database");
$sessionid = isset ($_POST['sessionid']) ? $_POST['sessionid'] : "";
$moduleid = isset ($_POST['moduleid']) ? $_POST['moduleid'] : "";
$teacherid = isset ($_POST['teacherid']) ? $_POST['teacherid'] : "";
$studentid = isset ($_POST['studentid']) ? $_POST['studentid'] : "";
$grade = isset ($_POST['grade']) ? $_POST['grade'] : "";
$orderfield = isset ($_POST['order']) ? $_POST['order'] : "";
$sessionid = mysql_real_escape_string($sessionid);
$moduleid = mysql_real_escape_string($moduleid);
$teacherid = mysql_real_escape_string($teacherid);
$studentid = mysql_real_escape_string($studentid);
$grade = mysql_real_escape_string($grade);
switch ($orderfield) {
case 'ordersessionid': $orderfield = 'gr.SessionId';
break;
case 'ordermoduleid': $orderfield = 'm.ModuleId';
break;
case 'orderteacherid': $orderfield = 's.TeacherId';
break;
case 'orderstudentid': $orderfield = 'gr.StudentId';
break;
case 'ordergrade': $orderfield = 'gr.Grade';
break;
}
$result = mysql_query("SELECT * FROM Module m INNER JOIN Session s ON m.ModuleId = s.ModuleId JOIN Grade_Report gr ON s.SessionId = gr.SessionId JOIN Student st ON gr.StudentId = st.StudentId WHERE ('$sessionid' = '' OR gr.SessionId = '$sessionid') AND ('$moduleid' = '' OR m.ModuleId = '$moduleid') AND ('$teacherid' = '' OR s.TeacherId = '$teacherid') AND ('$studentid' = '' OR gr.StudentId = '$studentid') AND ('$grade' = '' OR gr.Grade = '$grade') ORDER BY $orderfield ASC");
$num=mysql_numrows($result);
if(isset($_POST['submit'])) {
echo "<p>Your Search: <strong>Session ID:</strong> "; if (empty($sessionid))echo "'All Sessions'"; else echo "'$sessionid'";echo ", <strong>Module ID:</strong> "; if (empty($moduleid))echo "'All Modules'"; else echo "'$moduleid'";echo ", <strong>Teacher Username:</strong> "; if (empty($teacherid))echo "'All Teachers'"; else echo "'$teacherid'";echo ", <strong>Student Username:</strong> "; if (empty($studentid))echo "'All Students'"; else echo "'$studentid'";echo ", <strong>Grade:</strong> "; if (empty($grade))echo "'All Grades'"; else echo "'$grade'"; echo ", <strong>Order Results By:</strong>";if ($orderfield = 'gr.SessionId') echo " 'Session ID'"; else if ($orderfield = 'ordermoduleid') echo " 'Module Number' "; else if ($orderfield = 's.TeacherId') echo " 'Teacher Username' "; else if ($orderfield = 'gr.StudentId') echo " 'Student Username' "; else if ($orderfield = 'gr.Grade') echo " 'Grade' ";"</p>";
mysql_close();
?>
</body>
</html>
任何帮助将不胜感激。
I want to output the value from a dropdown menu using an echo but even though the dropdown menu works perfectly, the echo is not outputting the right value chosen from the drop down menu. The echo only output Session ID and that is it. Can you help me with this please. The echo is at the bottom of the code.
Below is my code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Exam Interface</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>
<p><strong>NOTE: </strong>If a search box is left blank, then the form will search for all data under that specific field</p>
<form action="exam_interface.php" method="post" name="sessionform"> <!-- This will post the form to its own page"-->
<p>Session ID: <input type="text" name="sessionid" /></p> <!-- Enter Session Id here-->
<p>Module Number: <input type="text" name="moduleid" /></p> <!-- Enter Module Id here-->
<p>Teacher Username: <input type="text" name="teacherid" /></p> <!-- Enter Teacher here-->
<p>Student Username: <input type="text" name="studentid" /></p> <!-- Enter User Id here-->
<p>Grade: <input type="text" name="grade" /></p> <!-- Enter Grade here-->
<p>Order Results By: <select name="order">
<option value="ordersessionid">Session ID</option>
<option value="ordermoduleid">Module Number</option>
<option value="orderteacherid">Teacher Username</option>
<option value="orderstudentid">Student Username</option>
<option value="ordergrade">Grade</option>
</select>
<p><input type="submit" value="Submit" name="submit" /></p>
</form>
<?php
$username="u0867587";
$password="31may90";
$database="mobile_app";
mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die("Unable to select database");
$sessionid = isset ($_POST['sessionid']) ? $_POST['sessionid'] : "";
$moduleid = isset ($_POST['moduleid']) ? $_POST['moduleid'] : "";
$teacherid = isset ($_POST['teacherid']) ? $_POST['teacherid'] : "";
$studentid = isset ($_POST['studentid']) ? $_POST['studentid'] : "";
$grade = isset ($_POST['grade']) ? $_POST['grade'] : "";
$orderfield = isset ($_POST['order']) ? $_POST['order'] : "";
$sessionid = mysql_real_escape_string($sessionid);
$moduleid = mysql_real_escape_string($moduleid);
$teacherid = mysql_real_escape_string($teacherid);
$studentid = mysql_real_escape_string($studentid);
$grade = mysql_real_escape_string($grade);
switch ($orderfield) {
case 'ordersessionid': $orderfield = 'gr.SessionId';
break;
case 'ordermoduleid': $orderfield = 'm.ModuleId';
break;
case 'orderteacherid': $orderfield = 's.TeacherId';
break;
case 'orderstudentid': $orderfield = 'gr.StudentId';
break;
case 'ordergrade': $orderfield = 'gr.Grade';
break;
}
$result = mysql_query("SELECT * FROM Module m INNER JOIN Session s ON m.ModuleId = s.ModuleId JOIN Grade_Report gr ON s.SessionId = gr.SessionId JOIN Student st ON gr.StudentId = st.StudentId WHERE ('$sessionid' = '' OR gr.SessionId = '$sessionid') AND ('$moduleid' = '' OR m.ModuleId = '$moduleid') AND ('$teacherid' = '' OR s.TeacherId = '$teacherid') AND ('$studentid' = '' OR gr.StudentId = '$studentid') AND ('$grade' = '' OR gr.Grade = '$grade') ORDER BY $orderfield ASC");
$num=mysql_numrows($result);
if(isset($_POST['submit'])) {
echo "<p>Your Search: <strong>Session ID:</strong> "; if (empty($sessionid))echo "'All Sessions'"; else echo "'$sessionid'";echo ", <strong>Module ID:</strong> "; if (empty($moduleid))echo "'All Modules'"; else echo "'$moduleid'";echo ", <strong>Teacher Username:</strong> "; if (empty($teacherid))echo "'All Teachers'"; else echo "'$teacherid'";echo ", <strong>Student Username:</strong> "; if (empty($studentid))echo "'All Students'"; else echo "'$studentid'";echo ", <strong>Grade:</strong> "; if (empty($grade))echo "'All Grades'"; else echo "'$grade'"; echo ", <strong>Order Results By:</strong>";if ($orderfield = 'gr.SessionId') echo " 'Session ID'"; else if ($orderfield = 'ordermoduleid') echo " 'Module Number' "; else if ($orderfield = 's.TeacherId') echo " 'Teacher Username' "; else if ($orderfield = 'gr.StudentId') echo " 'Student Username' "; else if ($orderfield = 'gr.Grade') echo " 'Grade' ";"</p>";
mysql_close();
?>
</body>
</html>
Any help will be much appreciated.
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在每个实例中,您都会覆盖
$orderfield
,因为您使用的是=
而不是==
。您不是测试$odrerfield
的值,而是分配$orderfield
的值。对随后的所有实例进行相同的更改。强烈建议将长回声线分成多条线。
In every instance, you overwrite
$orderfield
because you are using=
instead of==
. Rather than testing the value of$odrerfield
, you are assigning the value of$orderfield
.Make the same change for all the instances that follow. It is highly advisable to break up that long echo line into multiple lines.
您在上面的 if 条件上使用了错误的比较运算符,例如 - if($orderfield = 'ordermoduleid'),这些将类似于 - if($orderfield == 'ordermoduleid')
You have used wrong compare operator on the if condition above, like - if($orderfield = 'ordermoduleid'), these will be like - if($orderfield == 'ordermoduleid')