循环以i = 0开始。 if 和 else 完全相同。增加 i 并继续。 如果使用一点逻辑，整个块可以简化为 i++ （i = i % 3 没有任何效果，因为 i < 2 >）。
使用您发布的代码不可能获得 4 。
The loop starts with i = 0. Both the if and the else to exactly the same thing. Increment i and continue. If you use a bit of logic, the whole block can be reduced to i++ (i = i % 3 has no effect since i < 2).
It's not possible to get 4 with the code you posted.
此外，您的代码永远不会进入 if 块，因为条件是 i==2 在 for 循环中永远不可能为真，如下所示到那时循环就会退出。
所以你的代码相当于这样：
int main() {
int i=2;
for(i=0;i<2;i++) {
i++;
}
printf("%d",i);
}
The output cannot be 4 for the program you posted, because by the time the loop breaks, the value of i would be 2, not 4 and the loop will run exactly once.
Also, your code never enters the if block, because the condition is i==2 which can never be true inside the for loop, as by that time the loop would be exited.
So your code is equivalent to this:
int main() {
int i=2;
for(i=0;i<2;i++) {
i++;
}
printf("%d",i);
}
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循环以
i = 0开始。if和else完全相同。增加i并继续。如果使用一点逻辑，整个块可以简化为
i++（i = i % 3没有任何效果，因为i < 2>）。使用您发布的代码不可能获得
4。The loop starts with
i = 0. Both theifand theelseto exactly the same thing. Incrementiand continue.If you use a bit of logic, the whole block can be reduced to
i++(i = i % 3has no effect sincei < 2).It's not possible to get
4with the code you posted.对于您发布的程序，输出不能为
4，因为当循环中断时，i的值将是2，而不是 < code>4 并且循环将恰好运行一次。此外，您的代码永远不会进入
if块，因为条件是i==2在for循环中永远不可能为真，如下所示到那时循环就会退出。所以你的代码相当于这样：
The output cannot be
4for the program you posted, because by the time the loop breaks, the value ofiwould be2, not4and the loop will run exactly once.Also, your code never enters the
ifblock, because the condition isi==2which can never be true inside theforloop, as by that time the loop would be exited.So your code is equivalent to this: