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服务冻结活动？

发布于 2024-12-09 22:42:16 字数 97 浏览 3 评论 0原文

我有一个获取位置并将其发送到服务器的服务，我还有一个通过按钮启动和停止服务的活动。当我启动服务时，所有按钮都不起作用，一段时间后活动力关闭，提供等待或关闭的选项。什么可能导致问题？

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若能看破又如何 2024-12-16 22:42:16

我以前做过类似的事情......我不发布整个代码，只是主要的事情。这不会运行，我只是想给你一些想法，告诉你该做什么以及如何处理它。
魔法是在 sendUpdatesToUI 中完成的...我自己保存了所有不重要的方法，这些方法在您实现 LocationListener 时被覆盖 - 您最了解，您需要其中哪些方法。

它可能不会以这种方式运行，因为我剔除了所有无趣的东西，但它应该给

public class ServiceLocator extends Service implements LocationListener 
public static final String BROADCAST_ACTION = "my.app.isgreat";
private final Handler handler = new Handler();
private LocationManager locationManager;
Intent intent;

public void onCreate() {
    locationManager = (LocationManager) getSystemService(LOCATION_SERVICE);
    intent = new Intent(BROADCAST_ACTION);
}

public void onStart(Intent intent, int startId) {
    handler.removeCallbacks(sendUpdatesToUI);
    handler.postDelayed(sendUpdatesToUI, DEBUG_DELAY);

    locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER,
            DEBUG_DELAY, 3, this);

}

@Override
public void onDestroy() {
    super.onDestroy();
    handler.removeCallbacks(sendUpdatesToUI);
    locationManager.removeUpdates(this);
    locationManager = null;

你

//Here is the second thread, that won'z freeze your UI
//DisplayLogginInfo() sets all the values you wanna send
private Runnable sendUpdatesToUI = new Runnable() {
public void run() {
    DisplayLoggingInfo();
    handler.postDelayed(this, DEBUG_DELAY);
}

};

private void DisplayLoggingInfo() {
    intent.putExtra("long", String.format("%.4f", lastLocation.getLongitude()));
    sendBroadcast(intent);
}

一个想法，如何编程一个位置线程，这不会冻结你的 UI。

玩得开心

I did something like that before ... I dont post the whole code, jsut the main thing. This wont run, i just want to give you the idea, of what to llok for and how to handle it.
The magic is done in sendUpdatesToUI... I saved myself all the unimportant methods that are overwritten when you implement LocationListener - you know best, which of them you need.

class:

public class ServiceLocator extends Service implements LocationListener 
public static final String BROADCAST_ACTION = "my.app.isgreat";
private final Handler handler = new Handler();
private LocationManager locationManager;
Intent intent;

public void onCreate() {
    locationManager = (LocationManager) getSystemService(LOCATION_SERVICE);
    intent = new Intent(BROADCAST_ACTION);
}

public void onStart(Intent intent, int startId) {
    handler.removeCallbacks(sendUpdatesToUI);
    handler.postDelayed(sendUpdatesToUI, DEBUG_DELAY);

    locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER,
            DEBUG_DELAY, 3, this);

}

@Override
public void onDestroy() {
    super.onDestroy();
    handler.removeCallbacks(sendUpdatesToUI);
    locationManager.removeUpdates(this);
    locationManager = null;

}

//Here is the second thread, that won'z freeze your UI
//DisplayLogginInfo() sets all the values you wanna send
private Runnable sendUpdatesToUI = new Runnable() {
public void run() {
    DisplayLoggingInfo();
    handler.postDelayed(this, DEBUG_DELAY);
}

};

private void DisplayLoggingInfo() {
    intent.putExtra("long", String.format("%.4f", lastLocation.getLongitude()));
    sendBroadcast(intent);
}

It probably won't run that way, because I kicked out all the uninteresting stuff, but it should give you an idea, how to programm a locationthread, which won't freeze your UI.

Have fun

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