string.title() 认为撇号是一个新词的开头。为什么？

发布于 2024-12-09 21:16:00 字数 226 浏览 5 评论 0原文

>>> myStr="madam. i'm adam! i also tried c,o,m,m,a"
>>> myStr.title()
"Madam. I'M Adam! I Also Tried C,O,M,M,A"

这当然是不正确的。为什么撇号被视为新单词的开头。这是一个陷阱还是我假设标题的概念有问题？

原文

>>> myStr="madam. i'm adam! i also tried c,o,m,m,a"
>>> myStr.title()
"Madam. I'M Adam! I Also Tried C,O,M,M,A"

This is certainly incorrect. Why would an apostrophe be considered be considered as the start of a new word. Is this a gotcha or a am I assuming something wrong about the concept of title?

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生寂 2024-12-16 21:16:00

因为该实现是通过查看前一个字符来工作的，如果它是字母数字，则将当前字符小写，否则将其大写。也就是说，它比较简单，这是它的纯Python版本的样子：

def title(string):
    result = []
    prev_letter = ' '

    for ch in string:
        if not prev_letter.isalpha():
            result.append(ch.upper())
        else:
            result.append(ch.lower())

        prev_letter = ch

    return "".join(result)

Because the implementation works by looking at the previous character, and if it's alphanumeric it lower cases the current character, otherwise it upper cases it. That is to say, it's relatively simple, here's what a pure-python version of it looks like:

def title(string):
    result = []
    prev_letter = ' '

    for ch in string:
        if not prev_letter.isalpha():
            result.append(ch.upper())
        else:
            result.append(ch.lower())

        prev_letter = ch

    return "".join(result)

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倾城花音 2024-12-16 21:16:00

您可以使用：

string.capwords()

# Capitalize the words in a string, e.g. " aBc  dEf " -> "Abc Def".
def capwords(s, sep=None):
    """capwords(s, [sep]) -> string

    Split the argument into words using split, capitalize each
    word using capitalize, and join the capitalized words using
    join. Note that this replaces runs of whitespace characters by
    a single space.

    """
    return (sep or ' ').join(x.capitalize() for x in s.split(sep))

并且，由于 title() 与语言环境相关，请检查您的语言环境以查看这是否是故意的：

locale.localeconv()
返回本地约定的数据库作为
字典。
标题()
返回字符串的标题版本：单词开头为
大写字符，所有剩余的大小写字符均为小写。对于 8 位字符串，此方法与区域设置相关。

You could use:

string.capwords()

# Capitalize the words in a string, e.g. " aBc  dEf " -> "Abc Def".
def capwords(s, sep=None):
    """capwords(s, [sep]) -> string

    Split the argument into words using split, capitalize each
    word using capitalize, and join the capitalized words using
    join. Note that this replaces runs of whitespace characters by
    a single space.

    """
    return (sep or ' ').join(x.capitalize() for x in s.split(sep))

And, since title() is locale-dependent, check your locale to see if this is intentional:

locale.localeconv()
Returns the database of the local conventions as a
dictionary.
title()
Return a titlecased version of the string: words start with
uppercase characters, all remaining cased characters are lowercase. For 8-bit strings, this method is locale-dependent.

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