iOS 5 在 DatePicker 中选择日期

Question

我想在 DatePicker 中选择日期，但我遇到了 2 小时滞后的问题。

 // String From Date
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setTimeStyle:NSDateFormatterFullStyle];
[dateFormatter setDateStyle:NSDateFormatterFullStyle];
[dateFormatter setLocale:[NSLocale currentLocale]];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss ZZZ"];
NSDate *dateSelected = [datePicker date];
NSString *dateChoisie = [dateFormatter stringFromDate:dateSelected];
NSDate *dateFinal = [dateFormatter dateFromString:dateChoisie];

NSLog(@"dateSelected = %@", dateSelected);
NSLog(@"dateChoisie = %@", dateChoisie);
NSLog(@"dateFinal = %@", dateFinal);

结果 ：

2011-10-15 00:16:11.129 QuickEvent[25459:707] dateSelected = 2011-10-14 22:20:05 +0000
2011-10-15 00:16:11.132 QuickEvent[25459:707] dateChoisie = 2011-10-15 00:20:05 +0200
2011-10-15 00:16:11.138 QuickEvent[25459:707] dateFinal = 2011-10-14 22:20:05 +0000

Answer 1

尝试使用这种格式。

NSTimeZone *sourceTimeZone =[NSTimeZone systemTimeZone];
NSTimeZone *destinationTimeZone = [NSTimeZone timeZoneForSecondsFromGMT:(TIME_ZONE_THAT_YOU_WANTED*3600)];

NSInteger sourceSeconds =[sourceTimeZone secondsFromGMTForDate:date];
NSInteger destinationSeconds =[destinationTimeZone secondsFromGMTForDate:date];
NSTimeInterval interval = destinationSeconds - sourceSeconds;

NSDate *convertedDate =[[[NSDate alloc]initWithTimeInterval:interval sinceDate:date] autorelease];
return convertedDate;

例如，您可以将 TIME_ZONE_THAT_YOU_WANTED = -8 应用于基于纽约时区的时间

谢谢，
阿伦.