使用 GapSocket 将字符串发送到 tcp 套接字
我正在尝试使用 GapSocket 建立套接字连接并发送一些将数据（字符串）从 PhoneGap 传输到打开端口 8888 的计算机的 TCP 套接字。我已包含所有依赖项：
- 来自 cocoaasyncsocket 的 asyncsocket.m 和 asyncsocket.h 均是
- GapSocketCommand.m和 GapSocket 中的 GapSocketCommand.h
- 包含 GapSocket.js 并引用 www 文件夹下的 index.html 中的 js 文件。
以下是我的index.html 文件：
<!DOCTYPE html>
<html>
<head>
<title>Socket Test</title>
<script type="text/javascript" charset="utf-8" src="phonegap-1.1.0.js"></script>
<script type="text/javascript">
document.addEventListener("deviceready", function(){
var mySocket = new GapSocket(127.0.0.1, 8888);
mySocket.onopen = function(){ alert("Socket opened."); };
mySocket.send("some data here");
}, false);
</script>
</head>
<body>
</body>
它编译正常，不会引发任何依赖错误，并且能够在 iOS 模拟器上运行。在运行之前，我使用以下命令打开了 127.0.0.1（模拟器运行的计算机）上的端口 8888：
nc -l 127.0.0.1 8888
我可以使用 telnet 连接开放端口并发送数据：
远程登录127.0.0.1 8888
并发送以下数据：
eddy-2:~ eddy$ telnet 127.0.0.1 8888
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
test
test
回到 iOS 模拟器，它运行但没有发送任何内容，我不确定我是否正在执行初始化套接字的正确方法（我对 PhoneGap 都是新手）和 Xcode）。我按照自述文件中的步骤进行操作，但它没有提供太多上下文。
I am trying to establish a socket connection using GapSocket and send some data (strings) to a tcp socket from an PhoneGap to a computer with port 8888 open. I have included all dependencies:
- Both asyncsocket.m and asynsocket.h from cocoaasyncsocket
- Both GapSocketCommand.m and GapSocketCommand.h from GapSocket
- Included GapSocket.js and referenced the js file from index.html under www folder.
Following is my index.html file:
<!DOCTYPE html>
<html>
<head>
<title>Socket Test</title>
<script type="text/javascript" charset="utf-8" src="phonegap-1.1.0.js"></script>
<script type="text/javascript">
document.addEventListener("deviceready", function(){
var mySocket = new GapSocket(127.0.0.1, 8888);
mySocket.onopen = function(){ alert("Socket opened."); };
mySocket.send("some data here");
}, false);
</script>
</head>
<body>
</body>
It compiles okay and doesn't throw any dependency error and able to run on iOS Simulator. Before I run, I opened port 8888 on 127.0.0.1 (the machine that the Simulator runs) using:
nc -l 127.0.0.1 8888
I can connect the open port and send data by using telnet:
telnet 127.0.0.1 8888
with the following data send:
eddy-2:~ eddy$ telnet 127.0.0.1 8888
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
test
test
Coming back to the iOS Simulator, it runs but doesn't send anything out and I am not sure if I am doing the correct way of initializing the socket (I am new to both PhoneGap and Xcode). I followed steps on the readme but it doesn't provide much context.
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您需要在 cordova.plist 插件中包含一个带有 GapSocketCommand 字符串和值的条目
you need to include an entry in cordova.plist plugin with GapSocketCommand string and value
有两处错误：
ifconfig或类似工具找到您的 IP 地址）。例如，它应该如下所示：
另外，不要忘记在
PhoneGap.plist中注册插件。Two things are wrong:
ifconfigor similar).As an example, it should look something like this:
Also, don't forget to register the plugin in
PhoneGap.plist.