Monkey 修补和调度
我有以下情况，一个名为 enthought.chaco2 的模块，并且我有很多导入，例如 from enthought.chaco.api import ..
那么添加 < code>chaco.api 并使其分派到正确的位置？
例如，我尝试了一些方法：
import enthought.chaco2 as c2
import enthought
enthought.chaco = c2
但它不起作用。我可能必须创建一个真正的模块并将其添加到路径中；这是唯一的方法吗？
I have the following situation, a module called enthought.chaco2 and I have many imports, like from enthought.chaco.api import ..
so what's the quickest way to add chaco.api and make it dispatch to the correct one?
I tried a few things, for example:
import enthought.chaco2 as c2
import enthought
enthought.chaco = c2
but it doesn't work. I might have to create a real module and add it to the path; is that the only way?
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您正在寻找什么行为？
您可以使用
from enthought.chaco import api as ChacoApi，然后通过ChacoApi处理模块中的任何内容，例如ChacoApi.foo()或chaco_class = ChacoApi.MyClass()。您可以使用（但不推荐）
from enthought.chaco.api import *并将模块的所有内容添加到您的基本命名空间中。您可以将
__all__变量声明添加到chaco的__init__.py文件中，并让前面的示例（带有 *）仅导入您想要的内容输入列表__all__。或者您可以专门导入您现在可能使用的任何内容，我认为这完全没问题......
What is the behavior you're looking for?
You could use
from enthought.chaco import api as ChacoApiand then address any content from the module throughChacoApi, likeChacoApi.foo()orchaco_class = ChacoApi.MyClass().You could use (and that's not recommended)
from enthought.chaco.api import *and have all the content of the module added to your base namespace.You could add an
__all__variable declaration tochaco's__init__.pyfile and have the previous example (with the *) only import what you entered the list__all__.Or you could import specifically any content you might use the way you do right now which is perfectly fine in my opinion...