使用 ORDER BY 子句通过使用从下拉菜单中选择的值对查询进行排序
我想使用下拉列表来对查询结果进行排序。无论在下拉列表中选择什么选项,查询都将按所选选项的升序排列。我的查询工作正常,我只需要包含 ORDER BY 子句,我知道该子句位于 WHERE 子句之后。请仔细查看表格并请帮助我解决这个问题。
下面是代码:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Exam Interface</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>
<form action="exam_interface.php" method="post" name="sessionform"> <!-- This will post the form to its own page"-->
<p>Session ID: <input type="text" name="sessionid" /></p> <!-- Enter Session Id here-->
<p>Module Number: <input type="text" name="moduleid" /></p> <!-- Enter Module Id here-->
<p>Teacher Username: <input type="text" name="teacherid" /></p> <!-- Enter Teacher here-->
<p>Student Username: <input type="text" name="studentid" /></p> <!-- Enter User Id here-->
<p>Grade: <input type="text" name="grade" /></p> <!-- Enter Grade here-->
<p>Order Results By: <select name="order">
<option name="noorder">Don't Order Results</option>
<option name="ordersessionid">Session ID</option>
<option name="ordermoduleid">Module Number</option>
<option name="orderteacherid">Teacher Username</option>
<option name="orderstudentid">Student Username</option>
<option name="ordergrade">Grade</option>
</select>
<p><input type="submit" value="Submit" /></p>
</form>
<?php
$username="xxx";
$password="xxx";
$database="mobile_app";
mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die("Unable to select database");
$sessionid = $_POST['sessionid'];
$moduleid = $_POST['moduleid'];
$teacherid = $_POST['teacherid'];
$studentid = $_POST['studentid'];
$grade = $_POST['grade'];
$result = mysql_query("SELECT * FROM Module m INNER JOIN Session s ON m.ModuleId = s.ModuleId JOIN Grade_Report gr ON s.SessionId = gr.SessionId JOIN Student st ON gr.StudentId = st.StudentId WHERE ('$sessionid' = '' OR gr.SessionId = '$sessionid') AND ('$moduleid' = '' OR m.ModuleId = '$moduleid') AND ('$teacherid' = '' OR s.TeacherId = '$teacherid') AND ('$studentid' = '' OR gr.StudentId = '$studentid') AND ('$grade' = '' OR gr.Grade = '$grade')");
$num=mysql_numrows($result);
echo "<table border='1'>
<tr>
<th>Student Id</th>
<th>Forename</th>
<th>Session Id</th>
<th>Grade</th>
<th>Mark</th>
<th>Module</th>
<th>Teacher</th>
</tr>";
while ($row = mysql_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['StudentId'] . "</td>";
echo "<td>" . $row['Forename'] . "</td>";
echo "<td>" . $row['SessionId'] . "</td>";
echo "<td>" . $row['Grade'] . "</td>";
echo "<td>" . $row['Mark'] . "</td>";
echo "<td>" . $row['ModuleName'] . "</td>";
echo "<td>" . $row['TeacherId'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close();
?>
</body>
</html>
我尝试使用一个 switch 语句,该语句是好心发布给我的,但我无法让它工作。这就是我在下面尝试做的事情:
$orderfield = isset ($_POST['order']);
switch ($orderfield) {
case 'ordersessionid': $orderfield = 'gr.SessionId';
break;
case 'ordermoduleid': $orderfield = 'm.ModuleId';
break;
case 'orderteacherid': $orderfield = 's.TeacherId';
break;
case 'orderstudentid': $orderfield = 'gr.StudentId';
break;
case 'ordergrade': $orderfield = 'gr.Grade';
break;
}
$result = mysql_query("SELECT * FROM Module m INNER JOIN Session s ON m.ModuleId = s.ModuleId JOIN Grade_Report gr ON s.SessionId = gr.SessionId JOIN Student st ON gr.StudentId = st.StudentId WHERE ('$sessionid' = '' OR gr.SessionId = '$sessionid') AND ('$moduleid' = '' OR m.ModuleId = '$moduleid') AND ('$teacherid' = '' OR s.TeacherId = '$teacherid') AND ('$studentid' = '' OR gr.StudentId = '$studentid') AND ('$grade' = '' OR gr.Grade = '$grade') ORDER BY '$orderfield' ASC");
任何帮助都会非常感激。谢谢
I want to use a dropdown list to order the query result. Whatever option is chosen in the dropdown list, the query will be ordered in ascending order by the option selected. My query works fine, I just need to include the ORDER BY clause which I know comes after the WHERE clause. Please look at the form carefully and please help me on this problem.
Below is the code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Exam Interface</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>
<form action="exam_interface.php" method="post" name="sessionform"> <!-- This will post the form to its own page"-->
<p>Session ID: <input type="text" name="sessionid" /></p> <!-- Enter Session Id here-->
<p>Module Number: <input type="text" name="moduleid" /></p> <!-- Enter Module Id here-->
<p>Teacher Username: <input type="text" name="teacherid" /></p> <!-- Enter Teacher here-->
<p>Student Username: <input type="text" name="studentid" /></p> <!-- Enter User Id here-->
<p>Grade: <input type="text" name="grade" /></p> <!-- Enter Grade here-->
<p>Order Results By: <select name="order">
<option name="noorder">Don't Order Results</option>
<option name="ordersessionid">Session ID</option>
<option name="ordermoduleid">Module Number</option>
<option name="orderteacherid">Teacher Username</option>
<option name="orderstudentid">Student Username</option>
<option name="ordergrade">Grade</option>
</select>
<p><input type="submit" value="Submit" /></p>
</form>
<?php
$username="xxx";
$password="xxx";
$database="mobile_app";
mysql_connect('localhost',$username,$password);
@mysql_select_db($database) or die("Unable to select database");
$sessionid = $_POST['sessionid'];
$moduleid = $_POST['moduleid'];
$teacherid = $_POST['teacherid'];
$studentid = $_POST['studentid'];
$grade = $_POST['grade'];
$result = mysql_query("SELECT * FROM Module m INNER JOIN Session s ON m.ModuleId = s.ModuleId JOIN Grade_Report gr ON s.SessionId = gr.SessionId JOIN Student st ON gr.StudentId = st.StudentId WHERE ('$sessionid' = '' OR gr.SessionId = '$sessionid') AND ('$moduleid' = '' OR m.ModuleId = '$moduleid') AND ('$teacherid' = '' OR s.TeacherId = '$teacherid') AND ('$studentid' = '' OR gr.StudentId = '$studentid') AND ('$grade' = '' OR gr.Grade = '$grade')");
$num=mysql_numrows($result);
echo "<table border='1'>
<tr>
<th>Student Id</th>
<th>Forename</th>
<th>Session Id</th>
<th>Grade</th>
<th>Mark</th>
<th>Module</th>
<th>Teacher</th>
</tr>";
while ($row = mysql_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['StudentId'] . "</td>";
echo "<td>" . $row['Forename'] . "</td>";
echo "<td>" . $row['SessionId'] . "</td>";
echo "<td>" . $row['Grade'] . "</td>";
echo "<td>" . $row['Mark'] . "</td>";
echo "<td>" . $row['ModuleName'] . "</td>";
echo "<td>" . $row['TeacherId'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close();
?>
</body>
</html>
I have tried using a switch statement which was kindly posted to me but I couldn't get it to work. This is what I tried to do below:
$orderfield = isset ($_POST['order']);
switch ($orderfield) {
case 'ordersessionid': $orderfield = 'gr.SessionId';
break;
case 'ordermoduleid': $orderfield = 'm.ModuleId';
break;
case 'orderteacherid': $orderfield = 's.TeacherId';
break;
case 'orderstudentid': $orderfield = 'gr.StudentId';
break;
case 'ordergrade': $orderfield = 'gr.Grade';
break;
}
$result = mysql_query("SELECT * FROM Module m INNER JOIN Session s ON m.ModuleId = s.ModuleId JOIN Grade_Report gr ON s.SessionId = gr.SessionId JOIN Student st ON gr.StudentId = st.StudentId WHERE ('$sessionid' = '' OR gr.SessionId = '$sessionid') AND ('$moduleid' = '' OR m.ModuleId = '$moduleid') AND ('$teacherid' = '' OR s.TeacherId = '$teacherid') AND ('$studentid' = '' OR gr.StudentId = '$studentid') AND ('$grade' = '' OR gr.Grade = '$grade') ORDER BY '$orderfield' ASC");
Any help will be much appriciated. Thank You
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尝试
查看 http://php.net/manual/en/function.isset.php
更新
刚刚注意到...
ORDER BY
语句的参数不是参数而是表达式。换句话说,在查询中丢失$orderfield
周围的单引号,即Try
See http://php.net/manual/en/function.isset.php
Update
Just noticed... arguments to the
ORDER BY
statements aren't parameters but expressions. In other words, lose the single-quotes around$orderfield
in your query, ie看来您可能在这些选项上设置了错误的属性。您需要值,而不是名称:
或者...调试
找出它不起作用的原因:
您还可以在这一切发生之前检查
$_POST
数组。看看这个,看看你的所有表单值是否都在那里:Looks like you might have put the wrong attribute on those options. You want value, not name:
Or... Debug
Find out why it's not working:
You can also inspect the
$_POST
array before all this happens. Give this a look and see if all your form values are there: