可以通过 lxml 中子元素的文本值搜索 XML 元素吗？

发布于 2024-12-09 14:22:20 字数 825 浏览 1 评论 0原文

我有一个具有如下结构的 XML 文件：

<index>
    <compound kind="file">
        <name>file.c</name>
        <member kind="variable"><name>foo</name></member>
        <member kind="variable"><name>bar</name></member>
        ...
    </compound>
    <compound kind="file">
        <name>file.h></name>
        <member>...
    </compound>
</index>

我需要按文件成员名称进行搜索，但我无法弄清楚是否有一种方法可以避免迭代整个树。我的解决方案目前看起来像：

for f in xmlroot.iter("compound"):
    for m in f.iter("member"):
        if m.find("name").text == my_var_name:
            print "Found"

有没有办法使用 dict() 搜索来提高效率，因为我实际上有另一个上面的 for 循环，它会遍历变量列表来搜索，因此从性能角度来看，这真的很差。

将这两个 for 循环更改为单个 XPath 搜索会提高性能吗？

原文

I have an XML file with a structure like this:

<index>
    <compound kind="file">
        <name>file.c</name>
        <member kind="variable"><name>foo</name></member>
        <member kind="variable"><name>bar</name></member>
        ...
    </compound>
    <compound kind="file">
        <name>file.h></name>
        <member>...
    </compound>
</index>

I need to search by file member name but I can't figure out if there is a way that avoids iterating the entire tree. My solution currently looks like:

for f in xmlroot.iter("compound"):
    for m in f.iter("member"):
        if m.find("name").text == my_var_name:
            print "Found"

Is there a way to use a dict() search to improve efficiency because I actually have another for loop above that that goes through the list of variables to search for so performance-wise this is really poor.

Would changing those two for loops to a single XPath search improve performance?

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