DataMapper 和 Codeigniter 中的加密密码自定义规则

发布于 2024-12-09 11:59:12 字数 1536 浏览 0 评论 0原文

我正在使用 Codeigniter 2.0.3 和 DataMapper ORM 1.6.0。 CI 中的集成 DataMapper 已成功实现，除了密码加密外，一切正常。

我有一个名为 users.php 的模型，其中包含 Users 类。我还设置了验证规则：

var $validation = array(
    array(
        'field' => 'password',
        'label' => 'Password',
        'rules' => array('required', 'trim', 'unique', 'min_length' => 5, 'encrypt'),
    ),
    array(
        'field' => 'email',
        'label' => 'Email Address',
        'rules' => array('required', 'trim', 'valid_email')
    )
);

验证规则中的加密函数：

function _encrypt($field)
{
    // Don't encrypt an empty string
    if (!empty($this->{$field}))
    {
        // Generate a random salt if empty
        if (empty($this->salt))
        {
            $this->salt = md5(uniqid(rand(), true));
        }

        $this->{$field} = sha1($this->salt . $this->{$field});
    }
}

MySQL users 表结构：

id
email
password
last_login
created_on

我简单地通过控制器创建新用户：

$u = new Users();
$u->email = '[email protected]';
$u->password = 'mario';
$u->save();

编辑1：

的完整代码users.php 模型此处。

用户已成功存储在数据库中，但原始密码未加密。

我做错了什么？

谢谢，问候马里奥

原文

I am using Codeigniter 2.0.3 with DataMapper ORM 1.6.0. Integration DataMapper in CI has been implemented successfully and everything works fine, except password encryption.

I have model called users.php with class Users. I also have set validation rules:

var $validation = array(
    array(
        'field' => 'password',
        'label' => 'Password',
        'rules' => array('required', 'trim', 'unique', 'min_length' => 5, 'encrypt'),
    ),
    array(
        'field' => 'email',
        'label' => 'Email Address',
        'rules' => array('required', 'trim', 'valid_email')
    )
);

My encrypt function in validation rule:

function _encrypt($field)
{
    // Don't encrypt an empty string
    if (!empty($this->{$field}))
    {
        // Generate a random salt if empty
        if (empty($this->salt))
        {
            $this->salt = md5(uniqid(rand(), true));
        }

        $this->{$field} = sha1($this->salt . $this->{$field});
    }
}

MySQL users table structure:

id
email
password
last_login
created_on

I simple create new user via controller:

$u = new Users();
$u->email = '[email protected]';
$u->password = 'mario';
$u->save();

EDIT 1:

Full code of users.php model here.

User successfully stored in the database but with original password not encrypted.

What am I doing wrong?

Thanks, Regards
Mario

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

提笔落墨 2024-12-16 11:59:12

我相信您的 salt 类变量丢失了。在您的 _encrypt 函数中，您调用 $this->salt，但是，您从未在模型中声明 salt。我认为您需要在类中添加一个 salt 变量：

// in your Users model
<?php if (!defined('BASEPATH')) exit('No direct script access allowed.');

class Users extends DataMapper {

    var $table = 'users';
    var $has_one = array('profile');
    var $salt = 'B1471tU77IK1411'; // any string - helps to make password encryption stronger

I believe it's that your salt class variable is missing. In your _encrypt function, you call $this->salt, however, you never declare salt in the model. I think you need to add a salt variable in the class:

// in your Users model
<?php if (!defined('BASEPATH')) exit('No direct script access allowed.');

class Users extends DataMapper {

    var $table = 'users';
    var $has_one = array('profile');
    var $salt = 'B1471tU77IK1411'; // any string - helps to make password encryption stronger

回复收藏 0 原文