每当使用除法时，C 程序中的计算结果总是为 0
我使用两个不同的变量来除以 int 和 double 中的变量。当我使用以下内容时，这些工作正常：
int cost
cost = 40;
cost = (cost / 400) * 20 * 2;
对于此方法工作正常，我得到了正确的结果，即 4，但是当我使用变量 cost 并将其放入相反，像：
#define cost 40
int total_cost;
total_cost = (cost / 400) * 20 * 2;
这总是导致 0 对我来说，我不知道为什么。即使我将 printf 与 %d 或 %f 一起使用，这仍然会给出 0 的结果。
I'm using two different variable to divide in the calculation with the variable from int and double. These work fine when I use something like:
int cost
cost = 40;
cost = (cost / 400) * 20 * 2;
For this the method works fine and I get the right result which is 4, but when I use the variable cost and put it in the header instead, like:
#define cost 40
int total_cost;
total_cost = (cost / 400) * 20 * 2;
this always results in 0 for me and I don't know why. Even if I use printf with %d or %f this still gives me a result of 0.
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您正在进行整数除法 - 向下舍入。
因此：
返回零，因为
cost = 40和40 / 400向下舍入为零。你应该做的是使用像
double这样的浮点类型。编辑：
和
You are doing integer division - which rounds down.
Therefore:
is returning zero because
cost = 40and40 / 400rounds down to zero.What you should do is use a floating-point type like
double.EDIT:
and
运算顺序和整数除法。
整数除法总是截断。从数学上讲，40/400 = .1 - 但这不是整数。剩下的被扔掉，留下：
40 / 400 = 0。在您的示例中，运算顺序意味着首先完成除法。由于乘法和除法的顺序并不重要（从数学上来说），请尝试更改顺序：
首先发生乘法，最后发生除法，给出：
Order of operations, and Integer Division.
Integer Division always truncates. Mathematically, 40/400 = .1 - but that's not an integer. The remainder is thrown away, leaving you with:
40 / 400 = 0.Order of operations means that the division is done first, in your example. Since the order of multiplication and division doesn't matter too much (mathematically speaking), try changing the order:
Multiplication happens first, division last, giving you: