构造函数从 C# 到 Objective-C 的代码

Question

我们必须将 C# 代码转换为 Objective-C 代码，但我很难弄清楚如何创建一个不带参数的构造函数，而另一个则有 2 个参数。 这是我正在尝试转换的 C# 代码：

     namespace Account
{
class Program
{

    public class Account
    {

        private double balance;
        private int accountNumber;

        public Account()
        {
            balance = 0;
            accountNumber = 999;
        }

        public Account(int accNum, double bal)
        {
            balance = bal;
            accountNumber = accNum;
        }
        }
}

}

这就是我到目前为止对 Objective C 的了解，不确定它是否正确

     @interface classname : Account 
   {
@private double balance;
@private int accountNumber;

@public Account()
   }

接受任何我能得到的帮助，非常感谢，Danny

Answer 1

您只需提供两个初始值设定项，其采用一般形式：

@interface MONAccount : NSObject
@private
    double balance;
    int accountNumber;
}

/* declare default initializer */
- (id)init;

/* declare parameterized initializer */
- (id)initWithAccountNumber:(int)inAccountNumber balance:(int)inBalance;

@end

@implementation MONAccount

- (id)init
{
    self = [super init];
    /* objc object allocations are zeroed. the default may suffice. */
    if (nil != self) {
        balance = 0;
        accountNumber = 999;
    }
    return self;
}

- (id)initWithAccountNumber:(int)inAccountNumber balance:(int)inBalance
{
    self = [super init];
    if (nil != self) {
        balance = inBalance;
        accountNumber = inAccountNumber;
    }
    return self;
}

@end

Answer 2

Objective C 与其他语言有点不同。与其他语言相比，它的语法更奇怪。但从我所看到的来看，你似乎还没有学到太多关于 Objective-C 的知识。我建议您查看苹果的文档或获取一本书来实际了解 Objective-C 语法的工作原理。学习语法应该不会花太长时间，但您应该这样做。

@interface NSObject : Account
{
@private
double balance;
int accountNumber;
}
-(void)account; //No Arguements
-(void)account:(int)accNum withBalance:(double)bal; //2 Arguements

@implementation Program

-(void)account
{
balance = 0;
accountNumber = 999;
}

-(void)account:(int)accNum withBalance:(double)bal
{
balance = bal;
accountNumber = accNum;

}