Android webview调用loadurl时启动浏览器

发布于 2024-12-09 06:47:59 字数 602 浏览 1 评论 0原文

我创建了一个 Activity,它在 LinearLayout 中具有标题和 Web 视图。在 onResume() 方法中,它调用 webView.loadUrl(url)。问题在于,该 Activity 首先显示标题,而屏幕的其余部分为空白,然后启动设备浏览器并显示 URL 页面。我想看到的是标题下方的 WebView 中显示的页面。可能是什么问题?

编辑: 好的,做了一些进一步的搜索,发现了这个:

点击 URL 打开默认浏览器

它指向 此处的 WebView 教程

只需实现 Web 客户端并进行设置即可。

I created an Activity that has a title and a web view in a LinearLayout. In the onResume() method it calls webView.loadUrl(url). The problem is that the activity first shows the title with the rest of the screen blank, then the device browser is launched with the page for the URL. What I want to see is the page being shown in the WebView below the title. What could be the problem?

Edit:
Ok, did some further search and found this one:

Clicking URLs opens default browser

It points to the WebView tutorial here.

Just implement the web client and set it.

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评论(11

零崎曲识 2024-12-16 06:48:00

让你的活动像这样。

public class MainActivity extends Activity {
WebView browser;

@Override
 protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    // find the WebView by name in the main.xml of step 2
    browser=(WebView)findViewById(R.id.wvwMain);

    // Enable javascript
    browser.getSettings().setJavaScriptEnabled(true);  

    // Set WebView client
    browser.setWebChromeClient(new WebChromeClient());

    browser.setWebViewClient(new WebViewClient() {

        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
                view.loadUrl(url);
                return true;
                }
        });
     // Load the webpage
    browser.loadUrl("http://google.com/");
   }
}

Make your Activity like this.

public class MainActivity extends Activity {
WebView browser;

@Override
 protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    // find the WebView by name in the main.xml of step 2
    browser=(WebView)findViewById(R.id.wvwMain);

    // Enable javascript
    browser.getSettings().setJavaScriptEnabled(true);  

    // Set WebView client
    browser.setWebChromeClient(new WebChromeClient());

    browser.setWebViewClient(new WebViewClient() {

        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
                view.loadUrl(url);
                return true;
                }
        });
     // Load the webpage
    browser.loadUrl("http://google.com/");
   }
}
小ぇ时光︴ 2024-12-16 06:48:00

我遇到了同样的问题,我找到了解决方案
Android 关于 WebView 的官方文档

这是我的 onCreateView() 方法,这里我使用了两种方法来打开网址

方法1是在浏览器中打开url并

方法2是在您想要的WebView中打开url。

我的应用程序使用方法 2,这是我的代码:

public class MainActivity extends Activity {
   private WebView myWebView;

     @Override
     public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {

      View rootView = inflater.inflate(R.layout.fragment_webpage_detail, container, false);

      // Show the dummy content as text in a TextView.
      if (mItem != null) {

         /* Method : 1
          This following line is working fine BUT when we click the menu item then it opens the URL in BROWSER not in WebView */
         //((WebView)   rootView.findViewById(R.id.detail_area)).loadUrl(mItem.url);

        // Method : 2
        myWebView = (WebView) rootView.findViewById(R.id.detail_area); // get your WebView form your xml file
        myWebView.setWebViewClient(new WebViewClient()); // set the WebViewClient
        myWebView.loadUrl(mItem.url); // Load your desired url
    }

    return rootView;
}                                                                                               }

I was facing the same problem and I found the solution
Android's official Documentation about WebView

Here is my onCreateView() method and here i used two methods to open the urls

Method 1 is opening url in Browser and

Method 2 is opening url in your desired WebView.

And I am using Method 2 for my Application and this is my code:

public class MainActivity extends Activity {
   private WebView myWebView;

     @Override
     public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {

      View rootView = inflater.inflate(R.layout.fragment_webpage_detail, container, false);

      // Show the dummy content as text in a TextView.
      if (mItem != null) {

         /* Method : 1
          This following line is working fine BUT when we click the menu item then it opens the URL in BROWSER not in WebView */
         //((WebView)   rootView.findViewById(R.id.detail_area)).loadUrl(mItem.url);

        // Method : 2
        myWebView = (WebView) rootView.findViewById(R.id.detail_area); // get your WebView form your xml file
        myWebView.setWebViewClient(new WebViewClient()); // set the WebViewClient
        myWebView.loadUrl(mItem.url); // Load your desired url
    }

    return rootView;
}                                                                                               }
五里雾 2024-12-16 06:48:00

如果您看到空页面,请启用 JavaScript。

webView.setWebViewClient(new WebViewClient());
WebSettings webSettings = webView.getSettings();
webSettings.setJavaScriptEnabled(true);
webSettings.setDomStorageEnabled(true);
webView.loadUrl(url);

If you see an empty page, enable JavaScript.

webView.setWebViewClient(new WebViewClient());
WebSettings webSettings = webView.getSettings();
webSettings.setJavaScriptEnabled(true);
webSettings.setDomStorageEnabled(true);
webView.loadUrl(url);
耀眼的星火 2024-12-16 06:48:00

试试这个代码...

private void startWebView(String url) {

    //Create new webview Client to show progress dialog
    //When opening a url or click on link

    webView.setWebViewClient(new WebViewClient() {      
        ProgressDialog progressDialog;

        //If you will not use this method url links are opeen in new brower not in webview
        public boolean shouldOverrideUrlLoading(WebView view, String url) {              
            view.loadUrl(url);
            return true;
        }

        //Show loader on url load
        public void onLoadResource (final WebView view, String url) {
            if (progressDialog == null) {
                // in standard case YourActivity.this
                progressDialog = new ProgressDialog(view.getContext());
                progressDialog.setMessage("Loading...");
                progressDialog.show();
            }
        }
        public void onPageFinished(WebView view, String url) {
            try{
            if (progressDialog.isShowing()) {
                progressDialog.dismiss();
                progressDialog = null;
            }
            }catch(Exception exception){
                exception.printStackTrace();
            }
        }

    }); 

     // Javascript inabled on webview  
    webView.getSettings().setJavaScriptEnabled(true); 

    // Other webview options
    /*
    webView.getSettings().setLoadWithOverviewMode(true);
    webView.getSettings().setUseWideViewPort(true);
    webView.setScrollBarStyle(WebView.SCROLLBARS_OUTSIDE_OVERLAY);
    webView.setScrollbarFadingEnabled(false);
    webView.getSettings().setBuiltInZoomControls(true);
    */

    /*
     String summary = "<html><body>You scored <b>192</b> points.</body></html>";
     webview.loadData(summary, "text/html", null); 
     */

    //Load url in webview
    webView.loadUrl(url);
}

Try this code...

private void startWebView(String url) {

    //Create new webview Client to show progress dialog
    //When opening a url or click on link

    webView.setWebViewClient(new WebViewClient() {      
        ProgressDialog progressDialog;

        //If you will not use this method url links are opeen in new brower not in webview
        public boolean shouldOverrideUrlLoading(WebView view, String url) {              
            view.loadUrl(url);
            return true;
        }

        //Show loader on url load
        public void onLoadResource (final WebView view, String url) {
            if (progressDialog == null) {
                // in standard case YourActivity.this
                progressDialog = new ProgressDialog(view.getContext());
                progressDialog.setMessage("Loading...");
                progressDialog.show();
            }
        }
        public void onPageFinished(WebView view, String url) {
            try{
            if (progressDialog.isShowing()) {
                progressDialog.dismiss();
                progressDialog = null;
            }
            }catch(Exception exception){
                exception.printStackTrace();
            }
        }

    }); 

     // Javascript inabled on webview  
    webView.getSettings().setJavaScriptEnabled(true); 

    // Other webview options
    /*
    webView.getSettings().setLoadWithOverviewMode(true);
    webView.getSettings().setUseWideViewPort(true);
    webView.setScrollBarStyle(WebView.SCROLLBARS_OUTSIDE_OVERLAY);
    webView.setScrollbarFadingEnabled(false);
    webView.getSettings().setBuiltInZoomControls(true);
    */

    /*
     String summary = "<html><body>You scored <b>192</b> points.</body></html>";
     webview.loadData(summary, "text/html", null); 
     */

    //Load url in webview
    webView.loadUrl(url);
}
成熟稳重的好男人 2024-12-16 06:48:00

简单回答你可以这样使用

public class MainActivity extends AppCompatActivity {

     @Override
     protected void onCreate(Bundle savedInstanceState) {
         super.onCreate(savedInstanceState);
         WebView webView = new WebView(this);
         setContentView(webView);
         webView.setWebViewClient(new WebViewClient());
         webView.loadUrl("http://www.google.com");
   }
}

Simply Answer you can use like this

public class MainActivity extends AppCompatActivity {

     @Override
     protected void onCreate(Bundle savedInstanceState) {
         super.onCreate(savedInstanceState);
         WebView webView = new WebView(this);
         setContentView(webView);
         webView.setWebViewClient(new WebViewClient());
         webView.loadUrl("http://www.google.com");
   }
}
瞳孔里扚悲伤 2024-12-16 06:48:00

如果您使用 webChromeClient,我建议您同时使用 webChromeClientwebViewClient。因为webChromeClient不提供shouldOverrideUrlLoading。两者都用就可以了。

        webview.webViewClient = WebViewClient()
        webview.webChromeClient = Callback()

private inner class Callback : WebChromeClient() {
        override fun onProgressChanged(view: WebView?, newProgress: Int) {
            super.onProgressChanged(view, newProgress)
           
            if (newProgress == 0) {
                progressBar.visibility = View.VISIBLE
            } else if (newProgress == 100) {
                progressBar.visibility = View.GONE
            }
        }

    }

If you're using webChromeClient I'll suggest you to use webChromeClient and webViewClient together. because webChromeClient does not provides shouldOverrideUrlLoading. It is okay to use both.

        webview.webViewClient = WebViewClient()
        webview.webChromeClient = Callback()

private inner class Callback : WebChromeClient() {
        override fun onProgressChanged(view: WebView?, newProgress: Int) {
            super.onProgressChanged(view, newProgress)
           
            if (newProgress == 0) {
                progressBar.visibility = View.VISIBLE
            } else if (newProgress == 100) {
                progressBar.visibility = View.GONE
            }
        }

    }

北城挽邺 2024-12-16 06:48:00

我刚刚发现这取决于 URL 的格式:

我的代码只是使用

webview.loadUrl(url)

不需要

webView.setWebViewClient(new WebViewClient())

设置至少就我而言。
也许这对你们中的一些人有用。

I just found out that it depends on the formatting of the URL:

My code just uses

webview.loadUrl(url)

no need to set

webView.setWebViewClient(new WebViewClient())

at least in my case.
Maybe that's useful for some of you.

╰◇生如夏花灿烂 2024-12-16 06:48:00

我的问题最终是我需要先清除历史记录,然后才能在不打开外部浏览器的情况下在站点之间切换。

    @Override
    public void onPageFinished(WebView view, String url) {

        webView_.clearHistory();

        super.onPageFinished(webView_, url);
    }

My problem ended up being that I needed to do a clearHistory before I could switch between sites without opening an external browser.

    @Override
    public void onPageFinished(WebView view, String url) {

        webView_.clearHistory();

        super.onPageFinished(webView_, url);
    }
小耗子 2024-12-16 06:47:59

根据 Maudicus 和 Hit 的建议回答我的问题。

请在此处查看 WebView 教程。
只需实现 Web 客户端并将其设置在 loadUrl 之前即可。最简单的方法是:

myWebView.setWebViewClient(new WebViewClient());

要对 Web 内容进行更高级的处理,请考虑 ChromeClient。

Answering my question based on the suggestions from Maudicus and Hit.

Check the WebView tutorial here.
Just implement the web client and set it before loadUrl. The simplest way is:

myWebView.setWebViewClient(new WebViewClient());

For more advanced processing for the web content, consider the ChromeClient.

哥,最终变帅啦 2024-12-16 06:47:59

使用这个:

lWebView.setWebViewClient(new WebViewClient());

Use this:

lWebView.setWebViewClient(new WebViewClient());
○愚か者の日 2024-12-16 06:47:59

像这样使用:

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_dedline);

    WebView myWebView = (WebView) findViewById(R.id.webView1);
    myWebView.setWebViewClient(new WebViewClient());
    myWebView.loadUrl("https://google.com");
}

use like this:

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_dedline);

    WebView myWebView = (WebView) findViewById(R.id.webView1);
    myWebView.setWebViewClient(new WebViewClient());
    myWebView.loadUrl("https://google.com");
}
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