For循环写特殊符号
void printchars()
{
for (x=128;x<224;x++)
write(x);
我希望 x 是 write 函数中的一个字符。如何更改写入函数将 x 视为 char，而不是循环中的 int？
void printchars()
{
for (x=128;x<224;x++)
write(x);
I want the x to be a char in the write function. How can i change the x to be treated by the write functions as a char, but an int in the loop?
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如果您只是想去掉它的范围，那么将
x设为int有何意义？这就是为什么这是一个非常奇怪的请求。您应该将x设为unsigned char--for(unsigned char x = 128; x <224; ++ x) { ....如果您只是想确保调用
write<>的unsigned char模板特化，则可以这样调用：write( x); 如果没有，那么你将不得不使用类型转换：
write((unsigned char)x);编辑：我刚刚意识到你可能会做什么正在经历。我的猜测是，您最初使用
char但发现超过 127 的数字有问题。您可能应该使用unsigned char作为x而不是int或char。我编辑了我的答案以适应这一点。char的范围是 -128 到 +127。unsigned char的范围是 0-255。What is the point of making
xanintif you're just going to strip away its range? That's what makes this a very strange request. You should just makexaunsigned char--for(unsigned char x = 128; x <224; ++ x) { ....If you just want to ensure you're calling the
unsigned chartemplate specialization ofwrite<>, then call it like this:write<unsigned char>(x);If not, then you will have to use type casting:
write((unsigned char)x);Edit: I just realized what you might be experiencing. My guess is that you originally used
charbut found something wrong with numbers over 127. You should probably be usingunsigned charforxinstead of eitherintorchar. I edited my answer to accommodate this.charhas a range of -128 to +127.unsigned charhas a range of 0-255.将 x 转换为 char：
请注意，x 也可以是 char 作为循环计数器。
Cast x to a char:
Note that it is ok for x to be a char as the loop counter as well.