使用Boost状态图，如何无条件转换到某个状态？

发布于 2024-12-09 06:12:07 字数 742 浏览 1 评论 0原文

我有一个状态 A，一旦 A 的构造函数完成，我希望无条件转换到其下一个状态 B。这可能吗？

我尝试从构造函数发布一个事件，尽管它可以编译，但它不起作用。谢谢。

编辑：这是我到目前为止所尝试的：

struct A : sc::simple_state< A, Active >
{
    public:
        typedef sc::custom_reaction< EventDoneA > reactions;
        A()
        {
            std::cout << "Inside of A()" << std::endl;
            post_event( EventDoneA() );
        }

        sc::result react( const EventDoneA & )
        {
            return transit< B >();
        }
};

这会产生以下运行时断言失败：

Assertion failed: get_pointer( pContext_ ) != 0, file /includ
e/boost/statechart/simple_state.hpp, line 459

原文

I have a state A that I would like to transition to its next state B unconditionally, once the constructor of A has completed. Is this possible?

I tried posting an event from the constructor, which does not work, even though it compiles. Thanks.

Edit: Here is what I've tried so far:

struct A : sc::simple_state< A, Active >
{
    public:
        typedef sc::custom_reaction< EventDoneA > reactions;
        A()
        {
            std::cout << "Inside of A()" << std::endl;
            post_event( EventDoneA() );
        }

        sc::result react( const EventDoneA & )
        {
            return transit< B >();
        }
};

This yields the following runtime assertion failure:

Assertion failed: get_pointer( pContext_ ) != 0, file /includ
e/boost/statechart/simple_state.hpp, line 459

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默嘫て 2024-12-16 06:12:07

我已经用我的解决方案更新了我的OP，在这里我可以关闭问题。

问题是您无法从 simple_state 继承来实现所需的转换，您必须从 state 继承，然后需要您相应地修改构造函数。

struct A : sc::state< A, Active >
{
    public:
        typedef sc::custom_reaction< EventDoneA > reactions;
        A( my_context ctx ) : my_base( ctx )
        {
            std::cout << "Inside of A()" << std::endl;
            post_event( EventDoneA() );
        }

        sc::result react( const EventDoneA & )
        {
            return transit< B >();
        }
};

I've updated my OP with my solution, here it is so I can close the question.

The problem is that you cannot inherit from simple_state to achieve the desired transition, you must inherit from state, which then requires that you modify the constructor accordingly.

struct A : sc::state< A, Active >
{
    public:
        typedef sc::custom_reaction< EventDoneA > reactions;
        A( my_context ctx ) : my_base( ctx )
        {
            std::cout << "Inside of A()" << std::endl;
            post_event( EventDoneA() );
        }

        sc::result react( const EventDoneA & )
        {
            return transit< B >();
        }
};

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