Javascript Uncaught SyntaxError：Chrome 调试器中出现意外的标识符错误

发布于 2024-12-09 05:24:48 字数 1269 浏览 0 评论 0原文

我正在改编本教程中的XMLHttpRequest ：

var request = new XMLHttpRequest();  
request.open('GET', 'http://www.mozilla.org/', true);  
request.onreadystatechange = function (aEvt) {  
  if (request.readyState == 4) {  
     if (request.status == 200)  
       console.log(request.responseText)  
     else  
       console.log('Error', request.statusText);  
  }  
};  
request.send(null);

我的代码是：

var xhr = new XMLHttpRequest();
xhr.open("POST", "http://ting-1.appspot.com/submithandlertest", true);
xhr.onreadystatechange = function (aEvt) {
  if (xhr.readyState == 4) {
      if (xhr.status == 200) 
          console.log("request 200-OK");
          chrome.browserAction.setBadgeText ( { text: "done" } );
      else
          console.log("connection error");
          chrome.browserAction.setBadgeText ( { text: "ERR" } );
      setTimeout(function () {
      chrome.browserAction.setBadgeText( { text: "" } );
      }, 2000);
  }        
}        
xhr.send(formData);

但是 Chrome 调试器在 else 上给出了 Uncaught SyntaxError：意外标识符 错误。我做错了什么？谢谢！

原文

I am adapting the XMLHttpRequest from this tutorial:

var request = new XMLHttpRequest();  
request.open('GET', 'http://www.mozilla.org/', true);  
request.onreadystatechange = function (aEvt) {  
  if (request.readyState == 4) {  
     if (request.status == 200)  
       console.log(request.responseText)  
     else  
       console.log('Error', request.statusText);  
  }  
};  
request.send(null);

My code is:

var xhr = new XMLHttpRequest();
xhr.open("POST", "http://ting-1.appspot.com/submithandlertest", true);
xhr.onreadystatechange = function (aEvt) {
  if (xhr.readyState == 4) {
      if (xhr.status == 200) 
          console.log("request 200-OK");
          chrome.browserAction.setBadgeText ( { text: "done" } );
      else
          console.log("connection error");
          chrome.browserAction.setBadgeText ( { text: "ERR" } );
      setTimeout(function () {
      chrome.browserAction.setBadgeText( { text: "" } );
      }, 2000);
  }        
}        
xhr.send(formData);

But Chrome debugger gives a Uncaught SyntaxError: Unexpected identifier error on the else. What am I doing wrong? Thanks!

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暗藏城府 2024-12-16 05:24:48

您缺少 else 之前的结束 } 和 else 之后的开始 {，以及 if-else - 语句中的其他内容。

它适用于您的教程代码，因为 if-else - 语句中只有一行。当有多条线时，你必须正确地阻挡它们。（我个人建议始终这样做，即使只有一行代码。在我看来，它会增加可读性，并且当您决定有一天缩小代码时，您不会遇到问题）

尝试以下操作：

var xhr = new XMLHttpRequest();
xhr.open("POST", "http://ting-1.appspot.com/submithandlertest", true);
xhr.onreadystatechange = function (aEvt) {
  if (xhr.readyState == 4) {
      if (xhr.status == 200){
          console.log("request 200-OK");
          chrome.browserAction.setBadgeText ( { text: "done" } );
      }else{
          console.log("connection error");
          chrome.browserAction.setBadgeText ( { text: "ERR" } );
      setTimeout(function () {
      chrome.browserAction.setBadgeText( { text: "" } );
      }, 2000);
    }
  }        
};    
xhr.send(formData);

You are missing the closing } before and the opening { after the else, as well as the other ones in your if-else - statement.

It works on your tutorial code, because there's only one line in the if-else - statement. When there are multiple lines, you have to block them correctly. (I personally recommend to do this always, even if there's just one line of code. In my opinion it adds to readability and you will not have problems, when you decide to minify your code one day)

Try this:

var xhr = new XMLHttpRequest();
xhr.open("POST", "http://ting-1.appspot.com/submithandlertest", true);
xhr.onreadystatechange = function (aEvt) {
  if (xhr.readyState == 4) {
      if (xhr.status == 200){
          console.log("request 200-OK");
          chrome.browserAction.setBadgeText ( { text: "done" } );
      }else{
          console.log("connection error");
          chrome.browserAction.setBadgeText ( { text: "ERR" } );
      setTimeout(function () {
      chrome.browserAction.setBadgeText( { text: "" } );
      }, 2000);
    }
  }        
};    
xhr.send(formData);

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