C# 中图片框的圆角边缘

Question

如何在图片框控件中圆化边缘。我想要获得像椭圆一样的角度，但我不知道该怎么做。我使用 C#。谢谢！

Answer 1

将 1 个图片框放在表单上并编写此代码
您还可以更改宽度和高度旁边的负数以获得最佳结果

 System.Drawing.Drawing2D.GraphicsPath gp = new System.Drawing.Drawing2D.GraphicsPath();
            gp.AddEllipse(0, 0, pictureBox1.Width - 3, pictureBox1.Height - 3);
            Region rg = new Region(gp);
            pictureBox1.Region = rg;

Answer 2

是的，没问题，您可以通过其 Region 属性为控件指定任意形状。将新类添加到您的项目中并粘贴下面所示的代码。编译。将新控件从工具箱顶部拖放到窗体上。

using System;
using System.Drawing;
using System.Drawing.Drawing2D;
using System.Windows.Forms;

class OvalPictureBox : PictureBox {
    public OvalPictureBox() {
        this.BackColor = Color.DarkGray;
    }
    protected override void OnResize(EventArgs e) {
        base.OnResize(e);
        using (var gp = new GraphicsPath()) {
            gp.AddEllipse(new Rectangle(0, 0, this.Width-1, this.Height-1));
            this.Region = new Region(gp);
        }
    }
}

Answer 3

圆形边缘与圆角一样吗？

如果是这样，请查看 http://social.msdn.microsoft.com/forums/en-US/winforms/thread/603084bb-1aae-45d1-84ae-8544386d58fd

Rectangle r = new Rectangle(0, 0, pictureBox1.Width, pictureBox1.Height);
System.Drawing.Drawing2D.GraphicsPath gp = new System.Drawing.Drawing2D.GraphicsPath();
int d = 50;
gp.AddArc(r.X, r.Y, d, d, 180, 90);
gp.AddArc(r.X + r.Width - d, r.Y, d, d, 270, 90);
gp.AddArc(r.X + r.Width - d, r.Y + r.Height - d, d, d, 0, 90);
gp.AddArc(r.X, r.Y + r.Height - d, d, d, 90, 90);
pictureBox1.Region = new Region(gp);

Answer 4

谢谢你，汉斯。但我也需要光滑的外观。我对这个主题做了一些研究，但找不到解决方案。然后我尝试自己做，找到了下面的解决方案。也许其他人需要它。

protected override void OnPaint(PaintEventArgs e)
    {
        base.OnPaint(e);
        using (GraphicsPath gp = new GraphicsPath())
        {
            gp.AddEllipse(0, 0, this.Width - 1, this.Height - 1);
            Region = new Region(gp);
            e.Graphics.SmoothingMode = SmoothingMode.AntiAlias;
            e.Graphics.DrawEllipse(new Pen(new SolidBrush(this.BackColor), 1), 0, 0, this.Width - 1, this.Height - 1);
        }
    }