在 C 中使用 Strtok 获取字符串

发布于 2024-12-09 04:50:20 字数 306 浏览 1 评论 0原文

我想将一个字符串分成三部分。

gets(input);

printf("\n%s\n",input);

first = strtok (input, " ");
second = strtok ( NULL, " " );
others = "";
while(input != NULL){
    tmp = strtok ( NULL, " " );
    strcat(others,tmp);
}

像这样...所以我想将第一个单词、第二个单词放入字符串中，将其他单词放入字符串中。此代码失败，我该如何解决这个问题？

原文

I want to split a string to 3 parts.

gets(input);

printf("\n%s\n",input);

first = strtok (input, " ");
second = strtok ( NULL, " " );
others = "";
while(input != NULL){
    tmp = strtok ( NULL, " " );
    strcat(others,tmp);
}

like this... So i want to get first word, second word into a string and others in a string. This code fails, how can i resolve this?

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伪装你 2024-12-16 04:50:20

C 中的字符串并不神奇，它们是字符数组。您不能只是将 strcat 转换为只读的空字符串。相反，您必须提供自己的目标字符串：

char others[1000] = { 0 };
char * tmp;

// ...

while ((tmp = strtok(NULL, " ")) != NULL)
{
  strcat(others, tmp);
}

您还使用了 input 和 tmp 错误；在处理之前，您应该检查 strtok 的结果。

这有点危险，因为您无法控制结果字符串的长度。您应该使用 strncat 来代替，但这意味着您还必须计算附加字符的数量。

Strings in C aren't magic, they're character arrays. You cannot just strcat into a readonly, empty string. Rather, you have to provide your own target string:

char others[1000] = { 0 };
char * tmp;

// ...

while ((tmp = strtok(NULL, " ")) != NULL)
{
  strcat(others, tmp);
}

You also used input and tmp wrong; you should be checking the result of strtok before processing it.

This is somewhat dangerous since you have no control over the resulting string length. You should use strncat instead, but that means you'll also have to keep count of the appended characters.

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