在 Ruby 中从一个方法中结束另一种方法中的 while 循环？

Question

我正在用 Ruby 开发一个简单的基于文本的地下城游戏，但我遇到了一个障碍。基本上，我有一个房间，门锁着。钥匙在另一个房间找到，我希望找到钥匙后将门打开。

到目前为止，我得到的信息如下：

def chest_room
  puts "You are in a small, round room."
  puts "On the floor in front of you is a small wooden chest."
  puts "It does not appear to be locked."
  puts "What do you do?"
  chest_open = false

  while true
  prompt; next_move = gets.chomp
  if next_move == "open chest"
    chest_open = true
    puts "Inside the chest, you see a small, brass key."
    puts "What do you do?"
    prompt; next_move = gets.chomp
  elsif next_move == "take key" and chest_open
    key_present = true      
  puts "You take the key and slip it into a pocket."
    puts "What do you do?"
    prompt; next_move = gets.chomp
  elsif next_move == "go back"
    start()
  else puts "I don't understand you."
    puts "What do you do?"
    prompt; next_move = gets.chomp
    end
  end
end  

def start
  puts "You find yourself in a dank room lit by torches."
  puts "There are three doors leading out of here."
puts "What do you do?"
door_open = false
key_present = false
while true
  prompt; next_move = gets.chomp
  if next_move == "door 1"
    chest_room()
  elsif next_move == "door 2"
    dais()
  elsif next_move == "door 3" and not door_open
    puts "This door is securely locked."
    puts "You'll need to find some way of opening it before you can enter."
    puts "What do you do?"
    prompt; next_move = gets.chomp
  elsif next_move == "door 3" and key_present
    door_open = true
    puts "The key you found fits easily into the lock."
    puts "With a click, you unlock the door!"
    orb_room()
  else 
    puts "I don't understand you."
    puts "What do you do?"
    prompt; next_move = gets.chomp
    end
  end
end

有什么意见或建议吗？本质上，我想在找到钥匙后结束door_open = false循环，但我不知道如何在chest_room方法中设置door_open = true，然后从start方法调用它。谢谢！

Answer 1

你真正需要的是重新备份并思考设计。您有一个房间，它有一个“打开”或“关闭”属性。您有一把钥匙，并且需要钥匙来更改该打开/关闭属性的状态。

写下你想做什么，并考虑如何将其建模为房间和钥匙，这样你就会走上更好的轨道。

（不，我不想给你答案。弄清楚更重要。）

Answer 2

您遇到了范围问题。通过在它们前面放置@来创建door_open或key_present实例变量。然后任何方法都可以访问它们。也 case/when 比 if elsif 更干净

while !@key_present # @key_present can be modified in another method
  prompt; next_move = gets.chomp
  case
    when "door 1" == next_move then chest_room() # put constants first when comparing ==
    when "door 2" == next_move then dais()
    # more conditions
  end
end