在 Rails 应用程序中发出非阻塞 HTTP 请求

发布于 2024-12-08 21:43:50 字数 78 浏览 0 评论 0原文

有谁知道如何从 Rails 中发出非阻塞 HTTP 请求？我最终将需要响应主体，并试图避免提出新的框架以使事情变得简单。

谢谢

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红焚 2024-12-15 21:43:50

你可以这样做：

def async_post
  Thread.new do
    uri = URI('https://somewhere.com/do_something')
    response = Net::HTTP.post_form(uri, 'param1' => '1', 'param2' => '2')
    # do something with the response
  end
  # Execution continues before the response is received
end

You can do something like this:

def async_post
  Thread.new do
    uri = URI('https://somewhere.com/do_something')
    response = Net::HTTP.post_form(uri, 'param1' => '1', 'param2' => '2')
    # do something with the response
  end
  # Execution continues before the response is received
end

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丢了幸福的猪 2024-12-15 21:43:50

这不是非阻塞的，但你可以设置一个非常低的read_timeout。还要捕获由此产生的超时错误，这本身就是一个小的性能损失：

request = Net::HTTP::Get.new(url)
http = Net::HTTP.new(url.host, url.port)

http.read_timeout = 1

begin
  http.request(request)
rescue Timeout::Error => e
end

我不知道有什么基本的 Rails 机制可以发出非阻塞调用并接收响应。 Rails 与请求/响应周期密切相关，因此通常基本控制器执行路径将在 HTTP 调用返回之前结束。

This is not non-blocking, but you can set a very low read_timeout. Also catch the resulting timeout error, which itself is a small perf penalty:

request = Net::HTTP::Get.new(url)
http = Net::HTTP.new(url.host, url.port)

http.read_timeout = 1

begin
  http.request(request)
rescue Timeout::Error => e
end

I don't know of a basic rails mechanism that will both make a non-blocking call and receive the response. Rails is very much tied to the request/response cycle, so usually the basic controller execution path will have ended before the HTTP call returns.

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