如何检查网络应用程序中是否支持 google.navigation 意图/url 方案？

发布于 2024-12-08 21:13:05 字数 378 浏览 0 评论 0原文

我想知道，使用javascript，

location = "google.navigation:q="+myDestAddress;

在实际调用它之前是否支持这样的内容：以及它是否不恢复为普通的旧谷歌地图网址：

location = "http://maps.google.com/maps?saddr="+myStartAddress+"&daddr="+myDestAddress;

注意：我已经使用用户检查该设备是否是android设备代理，但这还不够，因为据我所知，“google.navigation”意图仅在美国受支持，并且仅在某些设备/操作系统版本上受支持。

谢谢！

原文

I would like to know, using javascript, if something like this:

location = "google.navigation:q="+myDestAddress;

is supported before actually invoking it, and if it is not revert to the plain old google maps url:

location = "http://maps.google.com/maps?saddr="+myStartAddress+"&daddr="+myDestAddress;

Note: I already check that the device is an android one using the user agent, but that is not enough as, as far as I know, the "google.navigation" intent is only supported in the US and only on some devices/OS versions.

Thanks!

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

吾性傲以野 2024-12-15 21:13:05

我想您正在寻找：

if(typeof google == "undefined" || typeof google.navigation == "undefined") {
    location = "http://maps.google.com/maps?saddr="+myStartAddress+"&daddr="+myDestAddress;
else {
    location = "google.navigation:q="+myDestAddress;
}

I think you're looking for:

if(typeof google == "undefined" || typeof google.navigation == "undefined") {
    location = "http://maps.google.com/maps?saddr="+myStartAddress+"&daddr="+myDestAddress;
else {
    location = "google.navigation:q="+myDestAddress;
}

回复收藏 0 原文

~没有更多了~