记录进程输出

发布于 2024-12-08 19:12:23 字数 318 浏览 0 评论 0原文

我使用方法system来启动一个进程。该进程的 pid 存储在文件 worker.pid 中，

但是我需要生成该进程的日志，如何存储该进程的输出？

正在使用以下命令创建进程：

system "bundle exec rake resque:work >> ./resque.log QUEUE=* PIDFILE=#{pid_file} &"

PS：我使用的是 ruby 1.8，BACKGROUND=yes 不起作用。 PS2：Linux平台

原文

I used the method system to start a process. the pid of that process is being stored in a file worker.pid

however I need to generate the log of this process, how can I store the output of this process?

the process is being created with this command:

system "bundle exec rake resque:work >> ./resque.log QUEUE=* PIDFILE=#{pid_file} &"

P.S.: I am using ruby 1.8, BACKGROUND=yes won`t work.
P.S.2: platform linux

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谁的年少不轻狂 2024-12-15 19:12:23

也许您正在寻找的是 IO.popen

这可以让你分叉一个子进程并通过 IO 对象访问它的输出

# fork off a one-off task
# and return the output as a string
ls = IO.popen("ls")
ls.read

# or return an array of lines
IO.popen("ls").readlines

# or create a continuing task
tail = IO.popen("tail -f /some/log/file.log")
loop do
  puts tail.gets
end

我建议你阅读文档，
但您也可以写入流，并做各种聪明的事情。

Maybe what you're looking for is IO.popen

This lets you fork off a subprocess and access it's output via an IO object

# fork off a one-off task
# and return the output as a string
ls = IO.popen("ls")
ls.read

# or return an array of lines
IO.popen("ls").readlines

# or create a continuing task
tail = IO.popen("tail -f /some/log/file.log")
loop do
  puts tail.gets
end

I suggest you read the documentation,
but you can also write to the stream, and do all sorts of clever stuff.

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