在curl命令中追加存储在变量中的URL

发布于 2024-12-08 14:21:45 字数 333 浏览 0 评论 0原文

当我在名为“域”的变量中存储名为“http://juke.com”的字符串时，我遇到了一些问题。其余的是存储在域服务器上的文件名。即 ipurl.php，使其成为“http://juboapp.com/ipurl.php”作为完整的 URL。

当我在下面的代码中调用这个变量时，它会卡在那里并且永远不会继续。基本上，当不处于尝试模式时，它会给出语法错误。有人可以告诉我它的正确语法是什么。

{set ipurl to (do shell script "curl -d \"ipurl=ipurl" & " \" & domain " \" /ipurl.php")}

原文

I am facing some problem when i am storing a string called "http://juke.com" in a variable called domain. and the rest is the filename stored on the domain server. i.e. ipurl.php so that it becomes "http://juboapp.com/ipurl.php" as complete URL.

And when i call this variable in the below code it stucks over there and never proceeds. Basically it gives a syntax error when not in try mode. Can someone tell me what is the proper syntax for it.

{set ipurl to (do shell script "curl -d \"ipurl=ipurl" & " \" & domain " \" /ipurl.php")}

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独守阴晴ぅ圆缺 2024-12-15 14:21:46

我想这就是你所追求的。

set domain to "http://juboapp.com"
set iPurl to (do shell script "curl " & domain & "/ipurl.php")

在这种情况下，URL 不需要用引号引起来。

I think this is what you're after.

set domain to "http://juboapp.com"
set iPurl to (do shell script "curl " & domain & "/ipurl.php")

URLs don't require quotes around them in this case.

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極樂鬼 2024-12-15 14:21:46

我已经得到答案了。我使用了 GET 方法而不是 POST 方法，并且它有效。虽然它也适用于 fireshadow52 的上述答案，但我无法让它使用其中的参数。不过还是谢谢。如果有人可以使用 POST 方法中的参数来实现此功能，请发表评论！

这是代码：

set domain to "http://juboapp.com"
set logindetails to domain & "/addplaylist.php?username=" & loginusername & ""
set logindetails to (do shell script "curl " & logindetails)

谢谢！

I have got the answer. I have used GET method instead of a POST method and it worked. Though it also works with the above answer from fireshadow52, but i wasn't able to get it to work with a parameter in it. thanks though. If anyone could get this working with a parameter in the POST method then please comment!

Here's the code:

set domain to "http://juboapp.com"
set logindetails to domain & "/addplaylist.php?username=" & loginusername & ""
set logindetails to (do shell script "curl " & logindetails)

Thanks!

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