C# 方法重载与接口参数
我只是好奇，以下示例被认为是“最佳实践”：我有一个数字数组或数字列表，并且希望将其提供给函数以返回平均值。
对于每种情况重载该方法是否更好：
double Average(int[] intArray){...}
double Average(uint[] uintArray){...}
double Average(double[] doubleArray){...}
...
double Average(List<int> intList){...}
...
或者，使用某种类型的接口是否更好：
double Average(IEnumerable arrayOrList)
{
// Branching logic for array or list.
}
谢谢！
编辑
平均值用作示例。我有几种数值算法，需要能够在各种数值数据上运行。
I'm just curious, what is considered the "best practice" for the following example: I have either a numeric array or numeric list and want to supply it to a function to return the average.
Is it better to overload the method for each case:
double Average(int[] intArray){...}
double Average(uint[] uintArray){...}
double Average(double[] doubleArray){...}
...
double Average(List<int> intList){...}
...
Or, is it better to use some type of interface:
double Average(IEnumerable arrayOrList)
{
// Branching logic for array or list.
}
Thanks!
EDIT
Average is used as an example. I have several numeric algorithms which need to be able to run on a variety of numeric data.
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查看 Enumerable.Average 扩展的各种重载指导方法：
这种风格的方法适用于任何实现 IEnumerable
where T : num约束，您需要为您希望支持的所有原始类型提供重载（Int32、Int64 ，单个，双，十进制，...)。Take a look at the various overloads of the Enumerable.Average Extension Method for guidance:
A method in this style works for any collection type that implements IEnumerable<T> (T[], List<T>, HashSet<T>, ReadOnlyCollection<T>, ...) and avoids the overhead incurred by a non-generic IEnumerable argument. Since C# doesn't have a
where T : numconstraint, you need to provide an overload for all primitive types you wish to support (Int32, Int64, Single, Double, Decimal, ...).接口将允许您提供数组或任何其他集合。不过，您可能希望使用强类型接口，例如
IEnumerable。An interface will allow you to supply an array or any other collection. You might want to use a strongly typed interface like
IEnumerable<int>though.假设
Average只是一个示例，您应该使用 IEnumerable 但使用您的数据类型重载该函数，如下所示：IEnumerable例如：
Assuming
Averageis just an example, you should use IEnumerable but overload the funciton with your data type, like so:IEnumerable<DataType>For example: