我只需要编辑一行正则表达式代码
以下代码有效，但如何编辑它以仅检测结束括号后的第一个大括号？
'/\{(([^{}]*|(?R))*)\}/'
示例：
if (1==1)
{
echo "testing {$username}";
}
问题在于它检测到所有大括号，甚至包括 $username 变量周围的大括号。所以我认为解决方案是检测第一个大括号之前是否有 ) 。我自己尝试了大约 20 种不同的方法，但无法使其发挥作用。如何对其进行编辑以仅检测 ) { 哦，如果第一个大括号和结束括号之间涉及空格和制表符（如果这很重要），请添加代码。谢谢。
the following code works but how can it be edited to only detect the first curly brace after an end parenthesis?
'/\{(([^{}]*|(?R))*)\}/'
Example:
if (1==1)
{
echo "testing {$username}";
}
The problem is that it detects ALL curly brackets, even the one surrounding the $username variable. So I think a solution would be to detect is there is a ) before the first curly bracket. I tried about 20 different things myself but cannot get it to work. How can it be edited to only detect ) { Oh and please add code if there are spaces and tabs involved inbetween the first curly bracket and end parenthesis if that matters. Thanks.
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您可以使用：
作为模式的一部分来检测像您的示例这样的简单情况。请注意，您不能使用可变长度的正向后查找，因此您不能将其更改为 (?<=)\s*){
我的模式仍然会拾取被注释掉的代码，并且不会' t 检测在 ) 和 { 之间有注释的代码。您不会想使用正则表达式来尝试检测此类情况。
You can use:
as part of your pattern to detect simple cases like your example. Note that you can't use a positive lookbehind of variable length though, so you can't alter it to (?<=)\s*){
My pattern will still pick up code that is commented out though, and won't detect code that has a comment between the ) and the {. You wouldn't want to use a regex to try to detect such cases.