将值从 2 个表传递到视图 Codeigniter

Question

我有一个功能可以显示买入和卖出列表。我试图在一页中显示这两个内容。 我从两个不同的表中获取值，我想将这两个值传递到同一个模板中，

有人可以建议如何操作吗？

控制器

function leads(){
    $this->load->model('listings');

    $data['mylists']=$this->member_functions->mine();
    $data['mylists2']=$this->member_functions->mine();

    $data['heading']='headings/heading_view';
    $data['body']='listbody';
    $data['nav']='right';

    $this->load->view('includes/template',$data);

}

模型

 function mine(){

    $mylists=$this->db->get('buy');

    if ($mylists->num_rows()>0){

        foreach ($mylists->result() as $a)
        {

            $data[]=$a;

        }
        return $data;
    }

    $mylists2=$this->db->get('sell');

    if ($mylists2->num_rows>0)
    {
        foreach ($mylists->result() as $b)
        {
            $data[]=$b;

        }

        return $data;

    }

}

视图

  <h2>Buy leads</h2>
                 <?php foreach ($mylists as $mylist):?>
         <p><?php echo "$mylist->type1 in $mylist->country as $mylist->buyid" ?></p>

       <?php endforeach;?>
            </div>
        <br />
            <h2>Sell leads</h2>
            <?php foreach ($mylists2 as $mylist2):?>
        <p><?php echo "$mylist2->type1 in $mylist2->country" ?></p>

       <?php endforeach;?>

Answer 1

您不能在同一个函数中使用 2 个 return 语句，因为每当遇到第一个语句时......好吧，函数就会返回并在那里停止。尝试返回包含 2 个结果的单个数组，例如：

Model:

function mine(){

    $mylists=$this->db->get('buy');

    if ($mylists->num_rows()>0){

        foreach ($mylists->result() as $a)
        {
            $data['res1'][]=$a;
        }
    }

    $mylists2=$this->db->get('sell');

    if ($mylists2->num_rows>0)
    {
        foreach ($mylists->result() as $b)
        {
            $data['res2'][]=$b;
        }
    }
  return $data;
}

Controller:

$data['lists']=$this->member_functions->mine();

在您看来，该数组的调用方式应类似于 $lists['res1 '] adn $lists['res2']