当密钥未知时获取对象？

发布于 2024-12-08 05:27:36 字数 374 浏览 1 评论 0原文

我有一些如下所示的 json，我正在尝试将其转换为 nsdictionaries。我的问题是 1、5 和 4 是键，具有不可预测的值。在不知道密钥的情况下，我如何获取每个对象 - {"id":"A","name":"Nike"}？

// JSON looks like:
{
"shops":
{
"1":{"id":"A","name":"Nike"},
"5":{"id":"G","name":"Apple"}
"4":{"id":"I","name":"Target"}
}
}

// how to step thru this?
NSArray *shopsArray = [[shopsString JSONValue] objectForKey:@"shops"];

原文

I have some json coming like the below, which i'm trying to turn into nsdictionaries. My problem is that the 1, 5 and 4 are keys, with unpredictable values. How would I get each object - {"id":"A","name":"Nike"} - without knowing the key?

// JSON looks like:
{
"shops":
{
"1":{"id":"A","name":"Nike"},
"5":{"id":"G","name":"Apple"}
"4":{"id":"I","name":"Target"}
}
}

// how to step thru this?
NSArray *shopsArray = [[shopsString JSONValue] objectForKey:@"shops"];

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

雄赳赳气昂昂 2024-12-15 05:27:36

从 objectForKey:@"shops" 返回的对象实际上是一个 NSDictionary 实例，而不是 NSArray，因为键实际上是字符串，而不是数字价值观。

出于您的目的，您只需对生成的 NSDictionary 调用 -allValues 即可。

NSDictionary *shops = [[shopsString JSONValue] objectForKey:@"shops"];

for(id obj in [shops allValues]) {
  //do stuff with obj...
}

编辑：如果您需要对值进行排序，那么您可以执行以下操作：

首先，将传入的 JSON 更改为这种结构：

{
  "shops":[
      {"key":"1", "id":"A","name":"Nike"},
      {"key":"5","id":"G","name":"Apple"},
      {"key":"4", "id":"I","name":"Target"}
  ]
}

然后，您可以对数组中的对象进行排序。

NSArray *shops = [[shopsString JSONValue] objectForKey:@"shops"];
for(NSDictionary *shop in shops) {
  NSString *key = [shop objectForKey:@"key"];
  //...
}

The returned object from objectForKey:@"shops" is actually an NSDictionary instance, not an NSArray, since the keys are actually strings, not numeric values.

For your purposes, you can simply call -allValues on the resulting NSDictionary.

NSDictionary *shops = [[shopsString JSONValue] objectForKey:@"shops"];

for(id obj in [shops allValues]) {
  //do stuff with obj...
}

EDIT: If you need ordering of the values, then you can do something like the following:

First, change the incoming JSON to this kind of structure:

{
  "shops":[
      {"key":"1", "id":"A","name":"Nike"},
      {"key":"5","id":"G","name":"Apple"},
      {"key":"4", "id":"I","name":"Target"}
  ]
}

Then, you can have ordering of the objects in the array.

NSArray *shops = [[shopsString JSONValue] objectForKey:@"shops"];
for(NSDictionary *shop in shops) {
  NSString *key = [shop objectForKey:@"key"];
  //...
}

回复收藏 0 原文

~没有更多了~